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Gruber P. Convex and Discrete Geometry

Gruber P. Convex and Discrete Geometry

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6 Mixed Volumes <strong>and</strong> Quermassintegrals 83<br />

Proof. First, let x ∈ C ∩ HC(u). Then x = λ1x1 +···+λmxm with suitable xi ∈ Ci.<br />

Clearly, u · xi ≤ hCi (u) for each i. In case λi = 0 we are free to choose xi ∈<br />

Ci ∩ HCi (u). It remains to show that, in case λi > 0, we also have xi ∈ Ci ∩ HCi (u).<br />

If this did not hold, then there is a λi > 0 where u · xi < hCi (u). Then,<br />

hC(u) = u · x = λ1u · x1 +···+λmu · xm

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