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Gruber P. Convex and Discrete Geometry

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image of<br />

the sun<br />

screen<br />

6 Mixed Volumes <strong>and</strong> Quermassintegrals 81<br />

Fig. 6.1. Camera obscura<br />

�<br />

sun<br />

diaphragm<br />

A similar question due to Tycho Brahe is about the form of the image of the sun on<br />

the screen of a camera obscura, depending on the shape of the diaphragm (Fig. 6.1).<br />

Implicitly using Minkowski addition, Kepler [575] solved Brahe’s problem by showing<br />

– in our terminology – the following: the image of the sun is of the form<br />

D + λB 2 , where D is a convex disc, a translate of the diaphragm. See Scriba <strong>and</strong><br />

Schreiber [923]. A similar phenomenon can be observed in sunshine at noon under<br />

a broad-leaved tree: the image of the sun on the ground consists of numerous rather<br />

round figures of the form P + λE, where P is approximately of polygonal shape,<br />

not necessarily convex, <strong>and</strong> E an ellipse. See Schlichting <strong>and</strong> Ucke [890].<br />

Properties of Minkowski Addition<br />

The following simple properties of Minkowski addition will be used frequently.<br />

Proposition 6.1. Let C, D ∈ C <strong>and</strong> λ ∈ R. Then C + D, λC ∈ C.<br />

Proof. We consider only C + D. To show the convexity of C + D,letu + x,v+ y ∈<br />

C + D where u,v ∈ C, x, y ∈ D, <strong>and</strong> let 0 ≤ λ ≤ 1. Then<br />

(1 − λ)(u + x) + λ(v + y) = � (1 − λ)u + λv � + � (1 − λ)x + λy � ∈ C + D<br />

by the convexity of C <strong>and</strong> D. Hence C+D is convex. It remains to show that C+D is<br />

compact. The Cartesian product C × D ={(x, y) : x ∈ C, y ∈ D} ⊆E d ×E d = E 2d<br />

is compact in E 2d . Being the image of the compact set C × D under the continuous<br />

mapping (x, y) → x + y of E 2d onto E d ,thesetC + D is also compact. ⊓⊔<br />

The following result relates addition <strong>and</strong> multiplication with positive numbers of<br />

convex bodies to addition <strong>and</strong> multiplication with positive numbers of the corresponding<br />

support functions.<br />

Proposition 6.2. Let C, D ∈ C <strong>and</strong> λ ≥ 0. Then<br />

Proof. Again, we consider only C + D:<br />

hC+D = hC + h D, hλC = λhC.<br />

hC+D(u) = sup{u · (x + y) : x ∈ C, y ∈ D}<br />

= sup{u · x : x ∈ C}+sup{u · y : y ∈ D}<br />

= hC(u) + h D(u) for u ∈ E d . ⊓⊔

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