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Gruber P. Convex and Discrete Geometry

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468 <strong>Geometry</strong> of Numbers<br />

S = � (x, z) : x ∈ E d , z ≥�x� 2�<br />

<strong>and</strong> choose a subset E ⊆ bd S such that its orthogonal projection into E d equals<br />

D. Define generalized polyhedra P, Q as follows: P = conv E <strong>and</strong> Q is the<br />

intersection of the support halfspaces of S at the points of E. Then P ⊆ S ⊆ Q,<br />

the orthogonal projections of the facets of P into E d give the Delone triangulation<br />

<strong>and</strong> the projections of the facets of Q into E d the Dirichlet–Voronoi tiling corresponding<br />

to D.<br />

Facet-to-Facet Tilings give Rise to Polyhedral Complexes<br />

A (generalized) polyhedral complex C is a family of (generalized) convex polyhedra<br />

in E d with the following property: The intersection of any two of its polyhedra is a<br />

face of each of these <strong>and</strong> any face of any of its polyhedra is contained in the family.<br />

The polyhedra of C are called the cells of C.<br />

The proof of the following result is easy <strong>and</strong> left to the reader.<br />

Proposition 32.3. The tiles of a locally finite, convex facet-to-facet tiling of E d are<br />

generalized convex polyhedra.<br />

Our next aim is to prove the following result of the <strong>Gruber</strong> <strong>and</strong> Ryshkov [451]:<br />

Theorem 32.1. Let T be a locally finite, convex facet-to-facet tiling of E d . Then T<br />

gives rise to a (generalized) polyhedral complex, that is, the family of all tiles <strong>and</strong> all<br />

faces of tiles, including the empty face, is a (generalized) polyhedral complex.<br />

Proof. We have to show that the intersection of any two faces of tiles is again a face<br />

of a tile.<br />

To prove this, we first show the following:<br />

(7) Let S, T ∈ T. Then S ∩ T is a face of both S <strong>and</strong> T .<br />

The main tool for the proof of (7) is the following proposition, the proof of which is<br />

left to the reader.<br />

(8) If a face of S contains a relative interior point of a convex subset of S (in its<br />

relative interior), then it contains (the relative interior of) this subset (in its<br />

relative interior).<br />

Let f ∈ relint(S ∩ T ). Since bd S is the disjoint union of the sets relint F, F a face<br />

of S, there is a face F of S with<br />

(9) f ∈ relint F.<br />

Similarly, there is a face G of T , such that<br />

(9) f ∈ relint G.<br />

For the proof of (7) it is sufficient to show that<br />

(10) F = G(<strong>and</strong>thusF = G = S ∩ T ).

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