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Gruber P. Convex and Discrete Geometry

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30 <strong>Convex</strong> Functions<br />

G(x). The proof of this statement is verbatim the same as for the corresponding<br />

statement (12) in the proof of Theorem 2.8.<br />

Fourth, call G differentiable at x ∈ C if G(x) is single-valued at x,sayG(x) = u,<br />

<strong>and</strong> if there is a real d × d matrix H, thederivative of G at x, such that the set<br />

G(y) − u − H(y − x) is contained in a neighborhood of o of radius o(�y − x�)<br />

as y → x, y ∈ C. The latter property will also be expressed in the form v =<br />

u + H(y − x) + o(�y − x�) as y → x, y ∈ C uniformly for v ∈ G(y),orintheform<br />

G(y) = u + H(y − x) + o(�y − x�) as y → x, y ∈ C.Clearly,ifG is differentiable<br />

at x, then it is continuous at x.<br />

(9) Let G be continuous at x ∈ C <strong>and</strong> let the single-valued mapping K =<br />

(I + G) −1 : D → E d be differentiable at w = x + u where u = G(x), <strong>and</strong><br />

such that its derivative A is non-singular. Then G is differentiable at x with<br />

derivative H = A −1 − I .<br />

The differentiability of K at w implies that<br />

(10) K (z) − K (w) = A(z − w) + r for z ∈ D, where �r�/�z − w� is arbitrarily<br />

small if �z − w� is sufficiently small.<br />

For a real d × d matrix B = (bik) define �B� =( � b 2 ik ) 1 2 . A result from linear<br />

algebra based on the Cauchy–Schwarz inequality then shows that �Bp�≤�B��p�<br />

for p ∈ E d . Thus �p� =�B −1 Bp�≤�B −1 ��Bp�, or<br />

(11) �Bp�≥ �p�<br />

�B −1 � for p ∈ Ed <strong>and</strong> each non-singular d × d matrix B.<br />

The following statement is a consequence of the continuity of G at x.<br />

(12) Let w = x +u ∈ D, u = G(x), z = y +v ∈ D, y ∈ C,v ∈ G(y) <strong>and</strong> thus<br />

x = K (w), y = K (z). Then �z − w� (≤ �v − u�+�y − x�) is arbitrarily<br />

small, uniformly for v ∈ G(y), if�y − x� is sufficiently small.<br />

For x, y,w,z as in (12), Propositions (10)–(12) show that<br />

�y − x� =�K (z) − K (w)� ≥�A(z − w)�−�r� ≥<br />

= �z − w�<br />

2�A −1 �<br />

if �y − x� is sufficiently small.<br />

�z − w�<br />

�A −1 �<br />

− �z − w�<br />

2�A −1 �<br />

Combining this with (10) yields the following proposition <strong>and</strong> thus completes the<br />

proof of statement (9):<br />

Let w = x + u ∈ D, u = G(x), z = y + v ∈ D, y ∈ C,v ∈ G(y) <strong>and</strong><br />

thus x = K (w), y = K (z). Then z − w = A −1 (y − x) + A −1 r,or<br />

v = u − (y − x) + A −1 (y − x) + A −1 r<br />

= u + (A −1 − I )(y − x) + A −1 r,<br />

where �A −1 r�/�y − x� is arbitrarily small, uniformly for v ∈ G(y), if<br />

�y − x� is sufficiently small.

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