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Gruber P. Convex and Discrete Geometry

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19 Lattice Polytopes 329<br />

Proposition 19.3. G d /H d is the free Abelian group generated by the cosets S0 +<br />

H d ,...,Sd + H d .<br />

Proof. By induction on d we prove that<br />

(9) S0 + H d ,...,Sd + H d generate G d /H d .<br />

For d = 0, (9) is trivial. Assume now that d > 0 <strong>and</strong> that (9) holds for d − 1. Let<br />

Ed−1 be embedded into Ed as usual (first d − 1 coordinates). Then Gd is generated<br />

by (the elements of) Gd p <strong>and</strong> Gd−1 . According to Proposition 19.1, Gd p is generated<br />

by Sd <strong>and</strong> Hd p <strong>and</strong> Gd−1 is generated by S0,...,Sd−1 <strong>and</strong> Hd−1 (⊆ Hd ) by the<br />

induction assumption. Thus Gd is generated by S0,...,Sd <strong>and</strong> Hd . This concludes<br />

the induction <strong>and</strong> thus yields (9).<br />

It remains to show that<br />

(10) S0 + H d ,...,Sd + H d are linearly independent (with respect to Z).<br />

A simple induction argument shows that<br />

� �<br />

n + i<br />

L(nSi) = for n ∈ N, i = 0,...,d.<br />

i<br />

For n ∈ N define φn : P Z d → R by<br />

φn(P) = L(nP) for P ∈ P Z d .<br />

Since the lattice point enumerator L : P Z d → R is a valuation, each φn is also a<br />

valuation. Let µn : G d /H d → R be the corresponding homomorphism, see Proposition<br />

19.2. If (10) did not hold, then<br />

for suitable integers ai, not all 0. Then<br />

a0S0 +···+ad Sd + H d = H d<br />

0 = µn(a0S0 +···+ad Sd + H d )<br />

= a0µn(S0 + H d ) +···+adµn(Sd + H d )<br />

= a0φn(S0) +···+adφn(Sd) = a0L(nS0) +···+ad L(nSd)<br />

� � � � � �<br />

n + 0 n + 1<br />

n + d<br />

= a0 + a1 +···+ad for n ∈ N.<br />

0<br />

1<br />

d<br />

Since � n+i �<br />

i is a polynomial in n of degree i, this can hold only if ad =···=a0 = 0.<br />

This contradiction concludes the proof of (10).<br />

Claims (9) <strong>and</strong> (10) together yield Proposition 19.3. ⊓⊔<br />

The Theorem of Betke <strong>and</strong> Kneser<br />

As a corollary of the above results, Betke <strong>and</strong> Kneser proved the following result.

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