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Gruber P. Convex and Discrete Geometry

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18 Theorems of Alex<strong>and</strong>rov, Minkowski <strong>and</strong> Lindelöf 305<br />

(2) V (s) = V � P(s) � is differentiable for s1,...,sn > 0, <strong>and</strong><br />

∂V (s)<br />

= Ai(s) for i = 1,...,n.<br />

∂si<br />

The proof of the formula for the partial derivatives of V (s), in the case where<br />

Ai(s) = 0, is left to the reader. If Ai(s) >0, then, for sufficiently small |h|, the<br />

polytopes P(s1,...,si + h,...,sn) <strong>and</strong> P(s1,...,sn) differ by the convex hull of<br />

Fi(s1,...,si + h,...,sn) <strong>and</strong> Fi(s1,...,sn). Since Fi(s1,...,si + h,...,sn) tends<br />

to F(s1,...,sn) as h → 0 (with respect to the Hausdorff metric), the volume of the<br />

convex hull is Ai(s1,...,sn)|h|+o(|h|). Hence<br />

V (s1,...,si + h,...,sn) − V (s1,...,sn) = A(s1,...,sn)h + o(h) as h → 0.<br />

Now divide by h <strong>and</strong> let h tend to 0 to get the formula for the partial derivatives of<br />

V (s) in (2). From the formula <strong>and</strong> the continuity of Ai, the differentiability of V<br />

follows.<br />

The simplex<br />

�<br />

n�<br />

�<br />

(3) S = s : si ≥ 0, αisi = 1 ⊆ E n<br />

i=1<br />

is compact. Since V is continuous on S, it attains its maximum on S at a point of<br />

S, saya. Ifa �∈ relint S, at least one ai is 0 <strong>and</strong> thus o ∈ bd P(a) by (1). Choose a<br />

vector v �= o such that o ∈ int � P(a) + v � . Then<br />

P(a) + v = � x + v : ui · x ≤ ai, i = 1,...,n �<br />

= � y : ui · y ≤ ai + ui · v, i = 1,...,n �<br />

= P(b), where b = a + (u1 · v,...,un · v).<br />

Since o ∈ int � P(a) + v � = int P(b), we thus see that b1,...,bn > 0. Since a ∈ S,<br />

the equality in statement (ii) implies that<br />

n�<br />

i=1<br />

αibi =<br />

n�<br />

i=1<br />

αiai +<br />

Hence b ∈ relint S. We thus have shown that<br />

n�<br />

αi ui · v = 1.<br />

i=1<br />

V attains its maximum on S at the point b ∈ relint S.<br />

Propositions (2), (3) <strong>and</strong> the Lagrange multiplier theorem then yield<br />

�<br />

n�<br />

� ����s=b<br />

∂<br />

V (s) − λ αisi = Ai(b) − λαi = 0fori = 1,...,n,<br />

∂si<br />

i=1

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