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Gruber P. Convex and Discrete Geometry

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304 <strong>Convex</strong> Polytopes<br />

For other pertinent results, see Alex<strong>and</strong>rov [16]. See also the report in Schneider<br />

[907].<br />

Minkowski’s Existence <strong>and</strong> Uniqueness Theorem for <strong>Convex</strong> Polytopes<br />

Minkowski [739] proved the following result; the proof is taken from Alex<strong>and</strong>rov<br />

[16]. It makes use of the Lagrange multiplier theorem from calculus.<br />

Theorem 18.2. Let u1,...,un ∈ S d−1 <strong>and</strong> α1,...,αn > 0. Then the following<br />

statements are equivalent:<br />

(i) u1,...,un <strong>and</strong> α1,...,αn are the exterior normal unit vectors <strong>and</strong> the areas of<br />

the corresponding facets of a proper convex polytope P in Ed which is unique up<br />

to translation.<br />

(ii) u1,...,un are not contained in a halfspace whose boundary hyperplane contains<br />

o <strong>and</strong><br />

n�<br />

αiui = o.<br />

i=1<br />

Proof. (i)⇒(ii) Clearly, P = � x : ui · x ≤ h P(ui), i = 1,...,n � .Letx∈ P. If<br />

there were a vector u �= o such that ui · u ≤ 0fori = 1,...,n, then x + λu ∈ P for<br />

all λ ≥ 0. This contradicts the boundedness of P <strong>and</strong> thus proves the first assertion<br />

in (ii). To see the second assertion, note that<br />

�<br />

n�<br />

�<br />

· u = �<br />

αi ui · u − �<br />

αi ui · (−u) for each u ∈ S d−1 .<br />

i=1<br />

αiui<br />

ui ·u>0<br />

ui ·u0 <strong>and</strong> thus ui · u ≤ 0fori = 1,...,n,<br />

in contradiction to (ii), concluding � the proof of (1).<br />

For s1,...,sn ≥ 0, let Ai s = (s1,...,sn) � be the area of the (possibly empty)<br />

face Fi(s) = P(s) ∩{x : ui · x = si} of P(s). (IfFi(s) =∅, put Ai(s) = 0.) Then

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