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Gruber P. Convex and Discrete Geometry

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n=1<br />

13 The Space of <strong>Convex</strong> Bodies 235<br />

Here,<br />

� �<br />

∞�<br />

∞�<br />

µh(A) = lim inf h(diam Un) : Un ⊆ D, diam Un ≤ ε, A ⊆<br />

ε→+0<br />

where diam is the diameter with respect to the given metric δ.<br />

In this section we prove the result of B<strong>and</strong>t <strong>and</strong> Baraki.<br />

Non-Existence of Isometry-Invariant Measures on 〈C,δ H 〉<br />

A Borel measure µ on C is isometry-invariant with respect to δ H if<br />

µ(D) = µ � I (D) � for all Borel sets D ⊆ C <strong>and</strong> each isometry I : C → C<br />

with respect to δ H .<br />

These isometries have been determined by <strong>Gruber</strong> <strong>and</strong> Lettl [449], see Theorem 13.4<br />

below. This result shows that there are few isometries of 〈C,δ H 〉 into itself. Thus the<br />

condition that a measure µ on C is isometry-invariant is not too restrictive. In spite<br />

of this we have the following negative result of B<strong>and</strong>t <strong>and</strong> Baraki [66].<br />

Theorem 13.3. Let d > 1. Then there is no positive σ -finite Borel measure on C<br />

which is invariant with respect to all isometries of 〈C,δ H 〉 into itself.<br />

Proof. Assume that there is a positive σ -finite Borel measure µ on C which is<br />

isometry-invariant with respect to δ H .Let<br />

Cn = C(nB d ) ={C ∈ C : C ⊆ nB d } for n = 1, 2,...<br />

Since C is the union of the compact sets Cn <strong>and</strong> µ is positive, there is an n with<br />

(1) µ(Cn) >0.<br />

For this n we have the following:<br />

(2) C contains uncountably many pairwise disjoint<br />

isometric copies of Cn.<br />

To see this, we first show that<br />

(3) the sets Cn +[o, p] ={C +[o, p] :C ∈ Cn}, p ∈ 3nS d−1 ,<br />

are pairwise disjoint.<br />

If (3) did not hold, there are p, q ∈ 3nS d−1 , p �= q, such that C+[o, p] =D+[o, q]<br />

for suitable C, D ∈ Cn. Choose a linear form l on E d such that l(p) = 1, l(q) = 0.<br />

Let r ∈ C be such that<br />

l(r) = min{l(x) : x ∈ C}.<br />

Choose s ∈ D <strong>and</strong> 0 ≤ λ ≤ 1, such that r = s + λq. Choose t ∈ C <strong>and</strong> 0 ≤ ν ≤ 1,<br />

such that s + q = t + νp. Then t + νp − q + λq = r <strong>and</strong> thus<br />

l(t) + ν = l(t + νp − q + λq) = l(r) ≤ l(t).<br />

n=1<br />

Un<br />

��<br />

,

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