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Gruber P. Convex and Discrete Geometry

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y<br />

o x<br />

x ∨ y<br />

K<br />

12 Special <strong>Convex</strong> Bodies 221<br />

K + y<br />

Fig. 12.2. Positive cone, vector lattice<br />

(K + x) ∧ (K + y) = K + x ∨ y<br />

K + x<br />

x ∧ y � x, y <strong>and</strong> if z � x, y, then z � x ∧ y,<br />

<strong>and</strong> similarly for x ∨ y.<br />

V is a topological vector space if V is Hausdorff <strong>and</strong> the mappings (x, y) →<br />

x + y <strong>and</strong> (λ, x) → λx are continuous. Up to isomorphisms, E d is the only<br />

d-dimensional (real) topological vector space (forget the norm, but retain the<br />

topology).<br />

If the vector space V is ordered <strong>and</strong> topological, it is called an ordered topological<br />

vector space if the ordering is compatible with the topology in the sense that<br />

o � A ⇒ o � cl A for A ⊆ V.<br />

This is equivalent to the requirement that the positive cone is closed.<br />

In the following we consider the finite-dimensional case. Let K be a pointed<br />

closed convex cone in E d with apex o. Then there is a hyperplane H with o �∈ H<br />

<strong>and</strong> such that C = H ∩ K is a convex body. Clearly, K = pos C ={λx : λ ≥ 0,<br />

x ∈ C}. K is a simplicial cone if C is a simplex. It is easy to see that this definition<br />

is independent of the choice of H.<br />

Choquet’s Characterization of Topological Vector Lattices<br />

We conclude this section with a finite-dimensional case of Choquet’s theorem on<br />

vector lattices, see [208].<br />

Theorem 12.2. Let K be a pointed closed convex cone in E d with apex o which<br />

makes E d into an ordered topological vector space. Then the following statements<br />

are equivalent:<br />

(i) E d is a vector lattice with positive cone K .<br />

(ii) K is a simplicial cone with dim K = d.<br />

Proof. (i)⇒(ii) In the following the above properties <strong>and</strong> definitions will be applied<br />

several times without explicit reference. The first step is to show the following:<br />

(4) Let x, y ∈ E d . Then (K + x) ∩ (K + y) = K + x ∨ y.

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