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Gruber P. Convex and Discrete Geometry

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186 <strong>Convex</strong> Bodies<br />

Theorem 9.10. Let C ∈ Cp. Then the volume of the difference body D = C − C<br />

satisfies the inequalities,<br />

2 d � �<br />

2d<br />

V (C) ≤ V (D) ≤ V (C).<br />

d<br />

Proof. Lower estimate: The Brunn–Minkowski theorem easily yields<br />

V (D) = V (C − C) = V � C + (−C) � ≥ � V (C) 1 d + V (−C) 1 d<br />

= � 2V (C) 1 �d d d<br />

= 2 V (C).<br />

Upper estimate: Let 1C be the characteristic function of C. Unless indicated<br />

otherwise, integration is over Ed . By changing the order of integration we have:<br />

� ��<br />

� � ��<br />

�<br />

(1) 1C(y − x)1C(y) dy<br />

�<br />

dx = 1C(y) 1C(y − x) dx dy<br />

= 1C(y)V (C) dy = V (C) 2 .<br />

For each x, the integral<br />

�<br />

1C(y − x)1C(y) dy<br />

is 0, unless there is a point y such that y <strong>and</strong> y − x both belong to C. In this case<br />

x = y − (y − x) ∈ C − C = D. Hence (1) can be written in the form:<br />

� ��<br />

�<br />

(2) 1C(y − x)1C(y) dy dx = V (C) 2 .<br />

D<br />

For each point x ∈ D\{o}, let λ = λ(x) ∈ (0, 1] be such that z = λ −1 x ∈ bd D ⊆ D.<br />

Since z ∈ D = C − C, there are points p, q ∈ C with z = p − q. By convexity,<br />

(1 − λ)C + λp ⊆ C, (1 − λ)C + λq + x ⊆ C + x.<br />

Since λp − (λq + x) = λ(p − q) − x = λz − x = o, thesets(1−λ)C + λp <strong>and</strong><br />

(1 − λ)C + λq + x coincide <strong>and</strong> so both are contained in C ∩ (C + x). Thus:<br />

�<br />

(3) 1C(y − x)1C(y) dy = V � C ∩ (C + x) � ≥ V � (1 − λ)C �<br />

= (1 − λ) d V (C) = � 1 − λ(x) � d V (C).<br />

Substituting this into (2) implies that<br />

V (C) 2 �<br />

� �d ≥ 1 − λ(x) V (C) dx.<br />

Dividing by V (C) <strong>and</strong> noticing that<br />

D<br />

� 1 − λ(x) � d =<br />

�1<br />

λ(x)<br />

d(1 − t) d−1 dt,<br />

� d

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