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Gruber P. Convex and Discrete Geometry

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�<br />

B<br />

�<br />

� � � �<br />

grad f (x) · grad u(x) dx +<br />

B<br />

f (x)�u(x) dx =<br />

�L<br />

0<br />

9 Symmetrization 181<br />

f � x(s) �∂u � �<br />

x(s) dx,<br />

∂n<br />

where f <strong>and</strong> u are as above.<br />

To prove (3), let f be chosen as in (3). Then (2), Green’s formula, the equality<br />

f |K = 0, the Cauchy–Schwarz inequality for integrals <strong>and</strong> (1) yield the following:<br />

�<br />

�<br />

2 f (x) dx =− f (x)�u(x) dx<br />

Hence<br />

B<br />

B<br />

B<br />

�<br />

�<br />

� � � �<br />

= grad f (x) · grad u(x) dx −<br />

�<br />

≤ � grad f (x)� �grad u(x)� dx<br />

B<br />

⎛<br />

⎞<br />

�<br />

�<br />

� �<br />

≤ ⎝<br />

2 � �2dx grad f (x) dx grad u(x) ⎠<br />

B<br />

⎛<br />

⎞<br />

�<br />

� �<br />

= ⎝<br />

2dx<br />

grad f (x) T(B) ⎠<br />

B<br />

� 2 �<br />

B<br />

B<br />

1<br />

2<br />

T (B) ≥ � � �2dx .<br />

grad f (x)<br />

B<br />

.<br />

f (x) dx � 2<br />

Since (2), Green’s formula, u|K = 0 <strong>and</strong> (1) show that<br />

�<br />

�<br />

2 u(x) dx =− u(x)�u(x) dx<br />

we obtain<br />

B<br />

B<br />

B<br />

0<br />

L<br />

f � x(s) �∂u � �<br />

x(s) ds<br />

∂n<br />

�<br />

=<br />

�L<br />

� �2dx grad u(x) − u<br />

B<br />

0<br />

� x(s) �∂u � �<br />

x(s) ds<br />

∂n<br />

�<br />

=<br />

� �2dx grad u(x) = T (B),<br />

� �<br />

2 u(x) dx �2 B<br />

T (B) = � � �2dx .<br />

grad u(x)<br />

B<br />

1<br />

2

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