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Gruber P. Convex and Discrete Geometry

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Steiner’s formula in d − 1 dimensions then shows that<br />

6 Mixed Volumes <strong>and</strong> Quermassintegrals 109<br />

v � (C + λB d )|u ⊥� = v � C|u ⊥ + λB d |u ⊥�<br />

�d−1<br />

� �<br />

d − 1<br />

=<br />

wi(C|u<br />

i<br />

⊥ )λ i .<br />

i=0<br />

Since C|u ⊥ varies continuously with u <strong>and</strong> wi(·) is continuous, we may integrate<br />

over Sd−1 <strong>and</strong> Cauchy’s surface area formula, applied to C + λB d , shows that<br />

(4) S(C + λB d �d−1<br />

� � �<br />

d − 1 1<br />

) =<br />

wi(C|u<br />

i<br />

⊥ ) dσ(u)λ i for λ ≥ 0.<br />

i=0<br />

κd−1<br />

Sd−1 Since S(C + λB d ) = dW1(C + λB d ), Steiner’s formula for W1(·) yields the following,<br />

see Theorem 6.14:<br />

(5) S(C + λB d �d−1<br />

� �<br />

d − 1<br />

) = d<br />

Wi+1(C)λ<br />

i<br />

i for λ ≥ 0.<br />

i=0<br />

Finally, equating coefficients in (4) <strong>and</strong> (5), implies (3). ⊓⊔<br />

A Remark on the Proofs<br />

In the proofs of Steiner’s <strong>and</strong> Kubota’s formulae for quermassintegrals, we have<br />

expressed the same quantity in two different ways as polynomials. Hence these polynomials<br />

must be identical, i.e. corresponding coefficients coincide. This finally yields<br />

the desired formulas. Expressing the same quantity in different ways <strong>and</strong> equating is<br />

a common method of proof in integral geometry, see Santaló [881].<br />

Why are Quermassintegrals or Mean Projection Measures Called So?<br />

Iterating (3) with respect to the dimension, yields the general formulae of Kubota.<br />

These express the quermassintegrals Wi(C) of C as the mean of the (d − i)dimensional<br />

volumes of the projections of C onto (d − i)-dimensional linear subspaces.<br />

These volumes are called Quermaße in German.<br />

Blaschke’s Problem for Quermassintegrals<br />

We conclude this section with the following major problem which goes back to<br />

Blaschke [125].<br />

Problem 6.1. Determine the set �� W0(C), . . . , Wd−1(C) � : C ∈ C � ⊆ E d .<br />

In case d = 2 the solution is given by the isoperimetric inequality: The set in question<br />

is {(P, A) : P 2 ≥ 4π A, P, A ≥ 0}, where P <strong>and</strong> A st<strong>and</strong> for perimeter <strong>and</strong> area.<br />

The problem is open for d ≥ 3. For some references, see Hadwiger [468], Schneider<br />

[907], <strong>and</strong> Sangwine-Yager [877, 878].

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