CIB-W18 Timber Structures – A review of meeting 1-43 2 MATERIAL ...
CIB-W18 Timber Structures – A review of meeting 1-43 2 MATERIAL ...
CIB-W18 Timber Structures – A review of meeting 1-43 2 MATERIAL ...
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F112 and F122. It is however shown that for a practical criterion these<br />
terms can be neglected and only F166 and F266 remain for longitudinal<br />
tension.<br />
� For longitudinal compression at σc = 0, equivalent hardening by crack<br />
arrest, (high F112) as well as hardening by confined dilatation (showing<br />
a negative F122 and F12) may occur. This last type <strong>of</strong> hardening probably<br />
only occurs in the torsion tube test, because the negative F122 and<br />
F12 predict a compression peak that does not occur in the oblique grain<br />
test. For structural elements, this effect thus has to be neglected and the<br />
lower bound criterion with only F166 and F266 (and zero F12, F122<br />
and F112) applies also for compression in the radial plane as follows<br />
from the good fit.<br />
� Because in the tangential plane, the higher order terms can be zero, the<br />
quadratic polynomial eq.<br />
2 2<br />
� 6 �1 �1 �1 � � �<br />
S X X XX<br />
2<br />
� 2 �<br />
YY<br />
� 2 � 2 � � �<br />
Y Y<br />
2 , , , , 1<br />
� should be used as lower bound for the Codes in all cases, for timber and<br />
clear wood, and because the equation represents initial yield as well it<br />
will apply for the lower 5th percentile <strong>of</strong> the strength.<br />
� For large sized timber and glulam, where shear failure (or longitudinal<br />
tensile failure) may pass radial as well as in tangential directions in the<br />
same failure plane, the following will apply:<br />
2<br />
� 6 � � 2 �1 � � �1 �� �1 � � � 2 �� � 2 �<br />
1 c 2 � � 266 � c , 166 1 1 1 1 1<br />
, � � � � �� � , � � � � �� � � , �<br />
S � Y X � � X �� X � � Y �� Y �<br />
� where c166 and c266 follows from oblique-grain tests based on the<br />
measured Cd and Ct values: F166 = Ct/X' + Cd/X; F266 = Ct/Y' +<br />
Cd/Y.<br />
� The Norris equations are not generally valid and only apply for uniaxial<br />
loading, identical to the Hankinson equation with n = 2, when the<br />
right (mostly) fictive shear-strength is used. These equations thus<br />
should not be used any more.<br />
� Therefore, for tapered beams and for all other cases with determining<br />
<strong>of</strong>f-axis uni-axial strength, the general Hankinson equations for tension<br />
and compression (with n different from n = 2, depending on the measurements)<br />
should be used or the exact equations.<br />
28-6-1 F Lam, H Yee, J D Barrett<br />
Shear strength <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber<br />
Abstract<br />
An experimental study has been conducted to evaluate the longitudinal<br />
shear strength <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber using a two span<br />
five point bending test procedure. Three species groups, Douglas fir, Hemfir<br />
and Spruce-Pine-Fir, have been considered. Approximately 40% <strong>of</strong> the<br />
failures can be attributed to shear failures. Two test configurations have<br />
been considered: test span to specimen depth ratios <strong>of</strong> 6 and 5. American<br />
Society for Testing and Materials (ASTM) shear block tests have been<br />
conducted to evaluate the shear strength <strong>of</strong> small clear specimens. Based<br />
on the ASTM shear block test results, finite element analyses coupled with<br />
Weibull weakest link theory have been used to predict the median shear<br />
failure loads. Good agreement between predicted and measured median<br />
failure loads has been observed.<br />
Conclusions<br />
An experimental study was undertaken to evaluate the longitudinal shear<br />
strength <strong>of</strong> three species groups <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber<br />
using a two span five point bending test procedure. Two test configurations<br />
were studied: span to depth ratios <strong>of</strong> 6:1 and 5:1. Longitudinal shear<br />
type failure was achieved in approximately 40% <strong>of</strong> the test cases. Based<br />
on the ASTM shear block test results, finite element analyses coupled with<br />
Weibull weakest link theory was used to predict the median shear failure<br />
loads. Predicted and measured median failure loads agreed well with an<br />
maximum under prediction error <strong>of</strong> 13%.<br />
<strong>CIB</strong>-<strong>W18</strong> <strong>Timber</strong> <strong>Structures</strong> <strong>–</strong> A <strong>review</strong> <strong>of</strong> <strong>meeting</strong> 1-<strong>43</strong> 2 <strong>MATERIAL</strong> PROPERTIES page 2.107