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CIB-W18 Timber Structures – A review of meeting 1-43 2 MATERIAL ...

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F112 and F122. It is however shown that for a practical criterion these<br />

terms can be neglected and only F166 and F266 remain for longitudinal<br />

tension.<br />

� For longitudinal compression at σc = 0, equivalent hardening by crack<br />

arrest, (high F112) as well as hardening by confined dilatation (showing<br />

a negative F122 and F12) may occur. This last type <strong>of</strong> hardening probably<br />

only occurs in the torsion tube test, because the negative F122 and<br />

F12 predict a compression peak that does not occur in the oblique grain<br />

test. For structural elements, this effect thus has to be neglected and the<br />

lower bound criterion with only F166 and F266 (and zero F12, F122<br />

and F112) applies also for compression in the radial plane as follows<br />

from the good fit.<br />

� Because in the tangential plane, the higher order terms can be zero, the<br />

quadratic polynomial eq.<br />

2 2<br />

� 6 �1 �1 �1 � � �<br />

S X X XX<br />

2<br />

� 2 �<br />

YY<br />

� 2 � 2 � � �<br />

Y Y<br />

2 , , , , 1<br />

� should be used as lower bound for the Codes in all cases, for timber and<br />

clear wood, and because the equation represents initial yield as well it<br />

will apply for the lower 5th percentile <strong>of</strong> the strength.<br />

� For large sized timber and glulam, where shear failure (or longitudinal<br />

tensile failure) may pass radial as well as in tangential directions in the<br />

same failure plane, the following will apply:<br />

2<br />

� 6 � � 2 �1 � � �1 �� �1 � � � 2 �� � 2 �<br />

1 c 2 � � 266 � c , 166 1 1 1 1 1<br />

, � � � � �� � , � � � � �� � � , �<br />

S � Y X � � X �� X � � Y �� Y �<br />

� where c166 and c266 follows from oblique-grain tests based on the<br />

measured Cd and Ct values: F166 = Ct/X' + Cd/X; F266 = Ct/Y' +<br />

Cd/Y.<br />

� The Norris equations are not generally valid and only apply for uniaxial<br />

loading, identical to the Hankinson equation with n = 2, when the<br />

right (mostly) fictive shear-strength is used. These equations thus<br />

should not be used any more.<br />

� Therefore, for tapered beams and for all other cases with determining<br />

<strong>of</strong>f-axis uni-axial strength, the general Hankinson equations for tension<br />

and compression (with n different from n = 2, depending on the measurements)<br />

should be used or the exact equations.<br />

28-6-1 F Lam, H Yee, J D Barrett<br />

Shear strength <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber<br />

Abstract<br />

An experimental study has been conducted to evaluate the longitudinal<br />

shear strength <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber using a two span<br />

five point bending test procedure. Three species groups, Douglas fir, Hemfir<br />

and Spruce-Pine-Fir, have been considered. Approximately 40% <strong>of</strong> the<br />

failures can be attributed to shear failures. Two test configurations have<br />

been considered: test span to specimen depth ratios <strong>of</strong> 6 and 5. American<br />

Society for Testing and Materials (ASTM) shear block tests have been<br />

conducted to evaluate the shear strength <strong>of</strong> small clear specimens. Based<br />

on the ASTM shear block test results, finite element analyses coupled with<br />

Weibull weakest link theory have been used to predict the median shear<br />

failure loads. Good agreement between predicted and measured median<br />

failure loads has been observed.<br />

Conclusions<br />

An experimental study was undertaken to evaluate the longitudinal shear<br />

strength <strong>of</strong> three species groups <strong>of</strong> Canadian s<strong>of</strong>twood structural lumber<br />

using a two span five point bending test procedure. Two test configurations<br />

were studied: span to depth ratios <strong>of</strong> 6:1 and 5:1. Longitudinal shear<br />

type failure was achieved in approximately 40% <strong>of</strong> the test cases. Based<br />

on the ASTM shear block test results, finite element analyses coupled with<br />

Weibull weakest link theory was used to predict the median shear failure<br />

loads. Predicted and measured median failure loads agreed well with an<br />

maximum under prediction error <strong>of</strong> 13%.<br />

<strong>CIB</strong>-<strong>W18</strong> <strong>Timber</strong> <strong>Structures</strong> <strong>–</strong> A <strong>review</strong> <strong>of</strong> <strong>meeting</strong> 1-<strong>43</strong> 2 <strong>MATERIAL</strong> PROPERTIES page 2.107

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