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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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88_Extrema and the Geometric Applications of a Derivative [Ch. 8<br />

greatest and least values of the function throughout the doma<strong>in</strong><br />

of def<strong>in</strong>ition).<br />

849. !/ = rih&. 853 - V = x* on the <strong>in</strong>terval [ 1,3].<br />

--<br />

850. y = x(lOx). 854. y = 2x* + 3* 2<br />

12* + 1<br />

851. y= s<strong>in</strong> 4 A; + cos 4 A;. a) on the <strong>in</strong>terval f 1,6];<br />

b) on the <strong>in</strong>terval [10,12],<br />

852. # = arc cos x.<br />

855. Show that for positive values of *we have the <strong>in</strong>equality<br />

856. Determ<strong>in</strong>e the coefficients p and q of the quadratic tr<strong>in</strong>omial<br />

y*=x*+px + q so that this tr<strong>in</strong>omial should have a m<strong>in</strong>-<br />

imum t/ = 3 when Jt= 1. Expla<strong>in</strong> the result <strong>in</strong> geometrical terms.<br />

857. Prove the <strong>in</strong>equality<br />

Solution. Consider the function<br />

e* > 1 + x when x 4* 0.<br />

In the usual way we f<strong>in</strong>d lhat this function has a s<strong>in</strong>gle m<strong>in</strong>imum /(0)<br />

Hence,<br />

/(*)>/ (0) when x 0,<br />

and so e* > 1 +x when x ^ 0,<br />

as we set out to prove.<br />

Prove the <strong>in</strong>equalities:<br />

858. x ^< s<strong>in</strong> x < x when *>0.<br />

o<br />

859. cos*>l ^ when<br />

860. A: ~

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