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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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Sec. 6] Differentials of First and Higher Orders 71<br />

Sec. 6. Differentials of First and Higher Orders<br />

1. First-order differential. The differential (first-order) of a function<br />

y = f(x) is the pr<strong>in</strong>cipal part of its <strong>in</strong>crement, which part is l<strong>in</strong>ear relative<br />

to the <strong>in</strong>crement Ax = dx of the <strong>in</strong>dependent variable x. The differential of a<br />

Fig. 19<br />

function is equal to the product of its derivative by the differential of the<br />

<strong>in</strong>dependent variable<br />

whence<br />

dy--=y'dx,<br />

, dy<br />

uy<br />

dx '<br />

If MN is an arc of the graph of the function y = f(x) (Fig. 19), MT is the<br />

tangent at M. (x, y) and<br />

PQ = Ax-=dx,<br />

then the <strong>in</strong>crement <strong>in</strong> the ord<strong>in</strong>ate of the tangent<br />

and the segment AN<br />

Example 1. F<strong>in</strong>d<br />

y = 3x<br />

by.<br />

the <strong>in</strong>crement and the differential of the function<br />

2<br />

x.<br />

Solution. First method:<br />

or<br />

Hence,<br />

Second method:<br />

A// = 3 (x + Ax) 2<br />

(x + Ax)<br />

At/ = (6* 1) Ax + 3 (Ax) 2 .<br />

dy = (6x 1) Ax = (6x 1) dx.<br />

3x 2 + x<br />

t/' = 6x 1; df/ = j/'dx = (6x 1) dx.<br />

Example 2. Calculate At/ and dy of the function y = 3x 2<br />

and Ax = 0.01.<br />

and<br />

Solution. A/ = (6x l)-Ax + 3 (Ax) 2 = 5- 0.0 1 + 3- 2<br />

(0.01 = ) 0.0503<br />

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