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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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434<br />

Answers<br />

along the large lower side of the rectangle, and the y-axis, perpendicular to<br />

it <strong>in</strong> the middle. 1778. Solution. S=\ dv, on the other hand, 7^=a,<br />

u a<br />

J<br />

v t<br />

a at<br />

whence dt = dv, and consequently, the acceleration time is /=l- = S.<br />

1780. M*=: \ (xt)ktdt + Ax=j(l'x*). 1781. Q =0.12 TRI* 9 cal. H<strong>in</strong>t.<br />

Use the Joule-Lenz law.<br />

2<br />

1782. V = (i/<br />

Cha<strong>pt</strong>er VI<br />

x 2<br />

)*. 1783. S = -<br />

(x + t/) /"4z 2 -}-3 (xy) 2<br />

-f. _...<br />

4<br />

Oje// /? l/<br />

j^S. 1786. /

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