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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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Answer^ 429<br />

1594. -- . 1599. -- 1 I 600 - 1- 1601. 1 6(>2. ^rr^ 4-(^ + l^. 1603. 1.<br />

1604. z<br />

2 Z o 2<br />

.<br />

2 . 1605. z\ b z- I 606 - Solution. r(p+l)=C xPe~* dx. Apply<strong>in</strong>g<br />

the formula of <strong>in</strong>tegration by parts, we put *P U, e~ x dx = dv. Whence<br />

and<br />

du = px. p ~ l<br />

dx, v= e~*<br />

If p is a natural number, then, apply<strong>in</strong>g formula (*) p times and tak<strong>in</strong>g <strong>in</strong>to<br />

account that<br />

we get:<br />

t608 . ^7<br />

1>35 " (2fe<br />

2k 246<br />

2-4-6 2<br />

1-3-5 ... (2k<br />

, ii n = 2k-\- 1 is an odd number<br />

_ 63jt<br />

/ _ 128 .<br />

/<br />

9 " 3l5 ' 10 ~"<br />

512 '<br />

00<br />

is an even number;<br />

V W ... - 1609. ^B ^, '-Hr^ H<strong>in</strong>t. Put<br />

1610. a) Plus; b) m<strong>in</strong>us; c) plus H<strong>in</strong>t. Sketch the graph of the <strong>in</strong>tegrand for<br />

values of the argument on the <strong>in</strong>terval of <strong>in</strong>tegration 1611. a) First; b) second;<br />

c) first. 1612. ~ 1613.a. 1614. ~. 1615. -|<br />

1617. 2

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