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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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J481. ^-? .<br />

+ ln s<strong>in</strong>hxl |<br />

.<br />

1490. -1 */(?<br />

x^-'+fir<br />

1494. In<br />

1485. -<br />

1496. (coslnx + s<strong>in</strong>lnx).<br />

- '<br />

Answers 427<br />

1480.<br />

. 1483. .n |l+cot*|-co tje.<br />

r \ x. 1486. 4- 1" cosh 2x. 1487. *coth*4<br />

5<br />

1488. gL-^ + lln |e* 2|. 1489. i-arctan^^-<br />

1497 . f x 2<br />

lcos5*~ |s<strong>in</strong>5*V 1498. 1 [(^ 2) arc tan<br />

t499 ' ^^<br />

1501. fc a.<br />

r<br />

1502. vjg~.<br />

Cha<strong>pt</strong>er V<br />

1500.<br />

y x s<strong>in</strong> 5x + 3x cos 5x +<br />

-| In (2<br />

-'<br />

,<br />

1503. 3. 1504. 1505. 156.<br />

H<strong>in</strong>t. Divide the <strong>in</strong>terval from x=\ to x = 5 on the x-axis <strong>in</strong>to sub<strong>in</strong>tervals<br />

so that the abscissas of the po<strong>in</strong>ts of division should form a geo-<br />

=- s<strong>in</strong>a + s<strong>in</strong>2o+...+s<strong>in</strong>/io cos<br />

_l<br />

metric progression: x =^l, x l = x Lq t x 2 x bq*, . . ., x n = x$ n<br />

. 1506.<br />

In.<br />

H<strong>in</strong>t. See Problem 1505. 1507. 1 cos*. H<strong>in</strong>t. Utilize the formula<br />

^~ cos ( n-}--^ ) a 1 . 1508. 1) 3- =<br />

- r -; 2) = .<br />

2s<strong>in</strong> _<br />

1509. In*. 1510. -<br />

<strong>in</strong> a at? <strong>in</strong> o<br />

1512. -f- cos -. 1513. * = /<br />

x x x<br />

2 V 2; J da<br />

1511.<br />

1,2,3, ...). 1514. In 2. 1515. ~~ .<br />

o<br />

1516. ** 5-^ = 2 s<strong>in</strong>h*. 1517. s<strong>in</strong> x. 1518. . Solution. The sum<br />

1,2, /i 1 1/1,2, n 1\<br />

,<br />

^r-^V^ + 7T + ' ' ' + ~~T" J<br />

.<br />

may be<br />

4<br />

as mtc -<br />

gral sum of the function /(A:) = X on the <strong>in</strong>terval [0,1]. Therefore, lim s n<br />

n -*oo<br />

i<br />

[- rH--o-+."H-- \ may be regarded as the <strong>in</strong>tegral sum of<br />

\ a n n /<br />

-^ . 1519. In 2. Solution. The sum sn = -i- H \-^ + . . . =<br />

2<br />

"<br />

H<br />

n+1 /i +2 /I + M<br />

M 1+1 i+Ji 1 + J

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