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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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36_Introduction to <strong>Analysis</strong>_[Ch. 1<br />

302. Show that for X+OQ the rational <strong>in</strong>tegral function<br />

P (x) = a.x n<br />

n ~ l<br />

. + a,x +<br />

. . -f a n (<br />

is an <strong>in</strong>f<strong>in</strong>itely large quantity equivalent to the term of highest<br />

degree a xn .<br />

303. Let x*oo. Tak<strong>in</strong>g x to bean <strong>in</strong>f<strong>in</strong>ite of the first order,<br />

determ<strong>in</strong>e the order of growth of the functions:<br />

a) *>- 100* -1,000;<br />

b) 7+2-<br />

Sec. 5. Cont<strong>in</strong>uity<br />

of Functions<br />

c)<br />

1. Def<strong>in</strong>ition of cont<strong>in</strong>uity. A function / (x) is cont<strong>in</strong>uous when x =<br />

(or "at the po<strong>in</strong>t g"), if: 1) this function is def<strong>in</strong>ed at the po<strong>in</strong>t g, that is,<br />

there exists a number / (g); 2) there exists a f<strong>in</strong>ite limit lim f (x); 3) this limx-4<br />

it is equal to the value of the function at the po<strong>in</strong>t g, i.e.,<br />

Putt<strong>in</strong>g<br />

where Ag ^0, condition (1) may be rewritten as<br />

llmf (*) = /(). (1)<br />

*-*fc<br />

lim A/(g) = lim l/(g+ Ag)-f (g)] = 0. (2)<br />

or the function / (x) is cont<strong>in</strong>uous at the po<strong>in</strong>t g if (and only if) at this po<strong>in</strong>t<br />

to an <strong>in</strong>f<strong>in</strong>itesimal <strong>in</strong>crement <strong>in</strong> the argument there corresponds an <strong>in</strong>f<strong>in</strong>itesimal<br />

<strong>in</strong>crement <strong>in</strong> the function.<br />

If a function is cont<strong>in</strong>uous at every po<strong>in</strong>t of some region (<strong>in</strong>terval, etc.),<br />

then it is said to be cont<strong>in</strong>uous <strong>in</strong> this region.<br />

Example 1. Prove that the function<br />

y = s<strong>in</strong> x<br />

fs cont<strong>in</strong>uous for every value of the argument x.<br />

Solution. We have<br />

s<strong>in</strong><br />

Ay = s<strong>in</strong>

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