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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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404_Answers<br />

494. , . 495. -<br />

- .<br />

1 2xcosa + xt . 496.<br />

5 + 4 s<strong>in</strong>*<br />

499. /?* 500. s<strong>in</strong> 2xe s<strong>in</strong>'x .<br />

.<br />

.<br />

f<br />

1+cos 2 * 2<br />

a w *lna. 502. e*(acos p/ p s<strong>in</strong> pO- 503. e"x s<strong>in</strong> p*.<br />

504. e-*cos3x. 505. ^-'a-^fn 2xMna). 506. -l(/tanx (1 + l/Tosxln a).<br />

1+*- """<br />

(1 _)/.<br />

+ Ps<strong>in</strong>hpjf)'. 539. 6tanh 2 2x (1 tanh 2<br />

2x) 540. 2coth2x. 541. ^L<br />

542. 543. ^ . 544. -^- . 545. . 546. xarctanhx<br />

x y In 2 x 1 cos2x s<strong>in</strong>x 1 x 2<br />

547. xarcs<strong>in</strong>hx. 548. a) y'=l when x>0; y' = 1 when x < 0; y' (0) does<br />

not exist; b) '-,*,. 549. ,' =1 . 550. f'W- I {<br />

1 1^3 / 2<br />

552. y+ I 5 -. 553. 6n. 554. a) /_ (0) = -1, / + (0)=1; b) /. (0) = ,<br />

/ V (0)= =^; c) /I (0)= 1, /'+ (0)-0; d) /'_ (0) =/'+ (0) = 0, e) /'. (0) and<br />

/'+ (0) do not exist. 555. 1 x. 556. 2 + ^-. 557. 1. 558. 561. Solution.<br />

We have y' = e" x (1 x). S<strong>in</strong>ce e' x =^ t it follows that y' = -(lx)<br />

or xy'=y(\x) 566. (1 +2x)(l +3x) + 2(l+x) (1 +3x) + 3(x + l) (1 +2x).<br />

567<br />

* 2~

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