29.01.2013 Views

Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Answers 399<br />

200. 3. 201. 1 . 202. i- . 203. -1 . 204. 12. 205. . 206. --i . 207. 1.<br />

-|<br />

208. =:. 209. .<br />

. 210. -- 211. - 212. - 213. ---. 214. -<br />

.<br />

2 x 3 3 2 22'<br />

j/jt<br />

215. 0. 216. a) -^s\n2\ b) 0. 217. 3. 218. A .<br />

z 2 o Z<br />

2 19. 4". 220. Jt. 221. I .<br />

222. cos a. 223. s<strong>in</strong> a. 224. ji. 225. cos A:. 226. -- JL 227. a) 0; b) 1.<br />

228. A. 229. 1. 230. 0. 231.<br />

~:j4=. 232. I(rt 2-m 2<br />

). 233. . 234. 1. y<br />

235. 4 236. . 237. I. 238. ji. 239. i- . 240. 1. 241. 1. 242. -i<br />

o Jt 4 4 4<br />

243. 244.<br />

-|.<br />

245. 0. 246. e" 1<br />

. 247. e 2 . 248. e" 1<br />

. 249. "*.<br />

250. e*. 251.6.252. a) 1. Solution, lim (cos*) * = lim [1 (1 cos x)]<br />

X-+0 X-0<br />

Si nee lim V = 2 lim<br />

X-+Q<br />

2s<strong>in</strong> a<br />

"m<br />

= 2-1- lim 7=0, it follows<br />

v ^n *<br />

that lim (cos*) * = e 1. b) "/==-. Solution. As <strong>in</strong> the preced<strong>in</strong>g<br />

*->o V e<br />

i lim<br />

case (see a), lim (cos x)* = e . S<strong>in</strong>ce lim<br />

X-+0<br />

: 2<br />

= .<br />

lim = _J_, it follows that lim (cos*)* =

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!