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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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ANSWERS<br />

Cha<strong>pt</strong>er I<br />

1. Solution. S<strong>in</strong>ce a=(a b) + b t then a \ \|a| \b\ and \ab = & a I<br />

| | (^ 6 | |a |. Hence, |a & ^ a | | | | |.<br />

Besides, \a-b = | -6| = |a/ + |6 3. |. a) -2

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