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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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Sec. 2] Interpolation of Functions 375<br />

3132. Given the table<br />

s<strong>in</strong> 10 = 0.1736, s<strong>in</strong> 13 = 0.2250,<br />

s<strong>in</strong> 11 = 0.1908, s<strong>in</strong> 14 = 0.2419,<br />

s<strong>in</strong> 12 = 0.2079, s<strong>in</strong> 15 = 0.2588.<br />

Fill <strong>in</strong> the table by comput<strong>in</strong>g (with Newton's formula, for = 2)<br />

the values of the s<strong>in</strong>e every half degree.<br />

3133. Form Newton's <strong>in</strong>terpolation polynomial for a function<br />

represented by the table<br />

3134*. Form Newton's <strong>in</strong>terpolation polynomial for a function<br />

represented by the table<br />

F<strong>in</strong>d y for x = 5. 5. For what x will y =<br />

3135. A function is given by the table<br />

Form Lagrange's <strong>in</strong>terpolation polynomial<br />

and f<strong>in</strong>d the value of<br />

y for JC = 0.<br />

3136. Experiment has yielded the contraction of a spr<strong>in</strong>g (x mm)<br />

as a function of the load (P kg) carried by the spr<strong>in</strong>g:<br />

F<strong>in</strong>d the load that yields a contraction of the spr<strong>in</strong>g by 14 mm.

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