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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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Sec. 3] Differential Equations with Variables Separable 327<br />

Sec. 3. First-Order Differential Equations with Variables Separable.<br />

Orthogonal Trajectories<br />

1. First-order equations with variables separable. An equation with variables<br />

separable is a first-order equation of the type<br />

y' = f(x)g(y} (i)<br />

X (x) Y (y) dx + X, (x) Y, (y) dy = Q (!')<br />

Divid<strong>in</strong>g both sides of equation (1) by g(y) and mult<strong>ipl</strong>y<strong>in</strong>g by dx, we get<br />

- = f(x)dx Whence, by <strong>in</strong>tegrat<strong>in</strong>g, we get the general <strong>in</strong>tegral of equa-<br />

tion (1) <strong>in</strong> the form<br />

Similarly, divid<strong>in</strong>g both sides of equation (!') by X, (x) Y (y) and <strong>in</strong>tegrat<strong>in</strong>g,<br />

we get the general <strong>in</strong>tegral of (!') <strong>in</strong> the form<br />

If for some value y = yQ we have (r/ )=0, then the function y = ti Q<br />

is<br />

also (as is directly evident) a solution of equation (1) Similarly, the straight<br />

l<strong>in</strong>es x a and y-b will be the <strong>in</strong>tegral curves of equation (!'), if a and b<br />

are, respectively, the roots of the equations X, (*)() and Y = (*/) 0, by the<br />

ieft sides of which we had to divide the <strong>in</strong>itial equation.<br />

Example 1. Solve the equation<br />

In particular, f<strong>in</strong>d the solution that satisfies the <strong>in</strong>itial conditions<br />

Solution. Equation (3) may<br />

be written <strong>in</strong> the torm<br />

dx~~ x<br />

Whence, separat<strong>in</strong>g variables, we have<br />

and, consequently,<br />

In |<br />

y<br />

= In | | x\ + ln C |t<br />

where the arbitrary constant In C, is taken <strong>in</strong> logarithmic form. After tak<strong>in</strong>g<br />

antilogarithms we get the general solution<br />

where C= C,.<br />

When divid<strong>in</strong>g dividi by y we could lose the solution =0. but the latter is<br />

' ' -<br />

conta<strong>in</strong>ed <strong>in</strong> the formula ila (4) for C = 0.<br />

f<br />

'3 >

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