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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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290_Mult<strong>ipl</strong>e and L<strong>in</strong>e Integrals_[Ch. 7<br />

2372. Determ<strong>in</strong>e the level surfaces ot the scalar field<br />

U = arc s<strong>in</strong> -<br />

2373. Show that straight l<strong>in</strong>es parallel to a vector c are the<br />

vector l<strong>in</strong>es of a vector field a(P) = c t where c is a constant<br />

vector.<br />

2374. F<strong>in</strong>d the vector l<strong>in</strong>es of the field a = CD*// 4 CDJC/, where CD<br />

is a constant.<br />

2375. Derive the formulas:<br />

a) grad(C l i/ + C 2 K) = C 1 gradf/ + C 2 gradV, where C, and C 2<br />

are constants;<br />

b) gTad(UV) = Ugrad<br />

c) grad (t/<br />

2<br />

) = 26/ grad<br />

j\ AfU\ V grad(/ U<br />

d) grad =-*<br />

(^ J<br />

e) grad

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