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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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284_Mult<strong>ipl</strong>e and L<strong>in</strong>e Integrals_[Ch. 7<br />

c) X= k*x, Y = k*y, Z = k*z, where k = const (elastic<br />

force), and the <strong>in</strong>itial po<strong>in</strong>t of the path is located on the sphere<br />

2<br />

x* 4- # + z 2 2 = /?<br />

Sec. 10. Surface Integrals<br />

, while the term<strong>in</strong>al po<strong>in</strong>t is located on the sphere<br />

1. Surface <strong>in</strong>tegral of the first type. Let f (x, //, 2) be a cont<strong>in</strong>uous<br />

function and z=-cp(*, y) a smooth surface S.<br />

The surface <strong>in</strong>tegral of the first type is the limit of the <strong>in</strong>tegral sum<br />

.3<br />

'(x, //, z)dS= lim<br />

n -> 00 fas I<br />

where AS/ is the area of the /th element of the surface S, the po<strong>in</strong>t (*/, y lt<br />

z/) belongs to this element, and the maximum diameter of elements of partition<br />

tends to zero.<br />

The value of this <strong>in</strong>tegral is not dependent on the choice of side of the<br />

surface S over which the <strong>in</strong>tegration is performed.<br />

If a projection a of the surface S on the jo/-plane is s<strong>in</strong>gle-valued, that<br />

is, every straight l<strong>in</strong>e parallel to the z-axis <strong>in</strong>tersects the surface S at only<br />

one po<strong>in</strong>t, then the appropriate surface <strong>in</strong>tegral of the first type may be<br />

calculated from the formula<br />

S (a)<br />

Example 1. Compute the surface <strong>in</strong>tegral<br />

(*' y) dx dl J-<br />

where S is the surf ace of the cube 0

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