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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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22 Introdnction to <strong>Analysis</strong> (C/t. /<br />

Sec. 3. Lfmits<br />

1. The limit of a sequence. The number a is the limit of a sequence<br />

*! x lt .... X0, .... or<br />

lim x n a,<br />

n > oo<br />

if for any e>0 there is a number N = N (e) such that<br />

\xn a | < e when n> N.<br />

Example<br />

1. Show that<br />

Solution. Form the difference<br />

Evaluat<strong>in</strong>g<br />

if<br />

Urn 5L + 1.2. (1)<br />

n -* rt-r 1<br />

2* +1<br />

1<br />

the absolute value of this difference, we have:<br />

-2 1<br />

< e, (2)<br />

n>-\ = N (e).<br />

Thus, for every positive number there will be a number Af= 1 such<br />

that for n > N we will have <strong>in</strong>equality (2) Consequently, the number 2 is<br />

the limit of the sequence x n (2n-\- l)/(n-fl), hence, formula (1) is true.<br />

2. The limit of a function. We say that a function / (x) -*- A as x -+ a<br />

(A and a are numbers), or<br />

lim f(x) = A,<br />

x -a<br />

if for every 8 > we have 6 = 6 () > such that<br />

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