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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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224_Functions of Several Variables_[Ch. 6<br />

The question of the existence and character of a conditional extremum is<br />

solved on the basis of a study of the sign of the second differential of the<br />

Lagrange function:<br />

yi<br />

dx 2<br />

-<br />

dxdy<br />

for the given system of values of x, y, h obta<strong>in</strong>ed from (2) or the condition<br />

that dx and dy are related by the equation<br />

Namely, the function / (x t y) has a conditional maximum, if d*F 0. As a particular case, if the discrim<strong>in</strong>ant A<br />

of the function F (x, y) at a stationary po<strong>in</strong>t is positive, then at this po<strong>in</strong>t<br />

there is a conditional maximum of the function / (x, y), if A < (or C < 0),<br />

and a conditional m<strong>in</strong>imum, if A > (or C > 0)<br />

In similar fashion we f<strong>in</strong>d the conditional extremum of a function of<br />

three or more variables provided there is one or several coupl<strong>in</strong>g equations<br />

(the number of which, however, must be less than the number of the variables)<br />

Here, we have to <strong>in</strong>troduce <strong>in</strong>to the Lagrange function as many undeterm<strong>in</strong>ed<br />

mult<strong>ipl</strong>iers factors as there are coupl<strong>in</strong>g equations.<br />

Example 2. F<strong>in</strong>d the extremum of the function<br />

z=:6 4* 3y<br />

provided the variables x and y satisfy the equation<br />

x*-\-y*=\<br />

Solution. Geometrically, the problem reduces to f<strong>in</strong>d<strong>in</strong>g the greatest and<br />

least values of the e-coord<strong>in</strong>ate of the plane z 6 4.v 3y for po<strong>in</strong>ts of its<br />

<strong>in</strong>tersection with the cyl<strong>in</strong>der ji 2<br />

-f// 2 =l<br />

We form the Lagrange function<br />

F(x, y)--=6 4x-3f/-l-M* 2 2<br />

-|-{/<br />

***follow<strong>in</strong>g<br />

system of We have T = ~ - 4 + 2>jr, = 3 + 2X#. The necessary conditions yield the<br />

equations:<br />

Solv<strong>in</strong>g this system we f<strong>in</strong>d<br />

and<br />

S<strong>in</strong>ce<br />

it follows that<br />

i<br />

:<br />

i - 5 _ 4<br />

X<br />

^-"2"' '-~5~'<br />

____^_ ___<br />

2 ~"<br />

2 1<br />

dx 2 -*"'<br />

^~""5"<br />

=0,<br />

dxdy<br />

f<br />

y<br />

dy 2<br />

1).

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