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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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202_Functions of Several Variables_[C/i. 6<br />

1920. F<strong>in</strong>d d'z if<br />

1921. F<strong>in</strong>d d*z if<br />

1922. F<strong>in</strong>d d*z if<br />

z~f(u, v), where u = ax, v = by^<br />

z = f(u, v), where u = xe y , v = ye*.<br />

z = e x cos y.<br />

1923. F<strong>in</strong>d the third differential of the function<br />

z = * cos y + y s<strong>in</strong> x.<br />

Determ<strong>in</strong>e all third partial derivatives.<br />

1924. F<strong>in</strong>d df(l 9 2) and d*f(l, 2) if<br />

f(x, y) = x 2<br />

1925. F<strong>in</strong>d d 2<br />

/(0, 0,0) if<br />

Sec. 8. Integration<br />

f(x 9 y, z) = x z<br />

+ xy + y* 4\nx \Q\ny.<br />

of Total Differentials<br />

t. The condition for a total differential. For an expression P (x, y)dx-}~<br />

+ Q(* y)dy> where the functions P (x, y) and Q (x, y) are cont<strong>in</strong>uous <strong>in</strong> a<br />

simply connected region D together with their first partial derivatives, to be<br />

(<strong>in</strong> D) the total differential ol some function u (x, y), it is necessary and sufficient<br />

that<br />

aq^ap<br />

dx ~~<br />

dy '<br />

Example t. Make sure that the expression<br />

is a total differential of some function, and f<strong>in</strong>d that function.<br />

Solution. In the given case, P = 2x + y t Q x+2y. Therefore, ,5 = -- =<br />

= 1, and, hence,<br />

where u is the desired function.<br />

It is given that - = 2jt + #; therefore,<br />

But on the other hand = x + y' (y) = x + 2y, whence q>' (y) = 2y, (p(f/) =<br />

and<br />

F<strong>in</strong>ally we have

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