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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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128 Indef<strong>in</strong>ite Integrals (Ch. 4<br />

Example<br />

3. F<strong>in</strong>d<br />

-1+1<br />

, x. 2 T<br />

Solution. Here, m=-^;n = - r ;p = =-:- -^; =2. Hence,<br />

we have here Case 2 <strong>in</strong>tegrability.<br />

The substitution<br />

yields * = (z 3<br />

where e y 1<br />

4<br />

I) ; dx=\2z* (z* \Y dz Therefore,<br />

+ J/T .<br />

F<strong>in</strong>d the <strong>in</strong>tegrals:<br />

1332.<br />

* z<br />

~ T 1335 '<br />

1333. r dx 133G<br />

,334. f_- * .<br />

i'<br />

337.{<br />

Sec. 7. Integrat<strong>in</strong>g Trigonometric Functions<br />

1. Integrals<br />

where m and n are <strong>in</strong>tegers.<br />

= 12 f ( 2 e ),fe=J2ef_<br />

0. f ^- T .<br />

2<br />

3 3<br />

J .v: (2 + JC<br />

)<br />

J ^ 3<br />

y 1+<br />

, r*<br />

1) If m^2/j+l is an odd positive number, then we put<br />

, n \<br />

of the form<br />

s '<br />

l(]Zk x cos " xd (cos ^) \ ( 1 cos 2<br />

x) k cos" xd (cos A:).<br />

We do the same if n is an odd positive number.<br />

Example 1.<br />

( s<strong>in</strong> 10 x cos 8 * dx = f s<strong>in</strong> 10 x (1<br />

s<strong>in</strong> 11 x s<strong>in</strong> 13 .v<br />

:<br />

'm.. 0)<br />

s<strong>in</strong> 2<br />

x) d (s<strong>in</strong> *) =

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