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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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U6__Indef<strong>in</strong>ite Integrals \Ch. 4<br />

1205. (f^+idx 1206*. f ff__<br />

y 4 x2<br />

J x J x2<br />

1208. Evaluate the <strong>in</strong>tegral<br />

r<br />

dx<br />

1207.<br />

J /*(!-*)<br />

by means of the substitution x=s<strong>in</strong> 2<br />

/.<br />

1209. F<strong>in</strong>d<br />

by apply<strong>in</strong>g the hyperbolic substitution x = as\n\\t.<br />

Solution. We have: ]Aa 2 + x2 = 2<br />

Solution. We have: ]Aa ]/~a 2 + x2 = 2<br />

]/~a + a2 suih 2 /=a cosh ^ and dx=a cosh /d/.<br />

Whence<br />

\ y a z<br />

-\-x 2 dx= ^ a cosh t-a cosh f ctf =<br />

S<strong>in</strong>ce<br />

and<br />

we f<strong>in</strong>ally get<br />

__ x ~<br />

a<br />

where C 1=^C In a is a new arbitrary constant.<br />

1210. F<strong>in</strong>d<br />

putt<strong>in</strong>g x = a cosh/.<br />

Sec. 3. Integration by Parts<br />

C<br />

}<br />

~~~2~<br />

A formula for <strong>in</strong>tegration on by parts. If H =

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