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Problems in Mathematical Analysis.pdf - pwp.net.ipl.pt

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96 Extrema and the Geometric Applications of a Derivative [Ch. 3]<br />

Sec. 4. Graph<strong>in</strong>g Functions by<br />

Characteristic Po<strong>in</strong>ts<br />

In construct<strong>in</strong>g the graph of a function, first f<strong>in</strong>d its doma<strong>in</strong> of def<strong>in</strong>ition<br />

and then determ<strong>in</strong>e the behaviour of the function on the boundary of this<br />

doma<strong>in</strong>. It is also useful to note any peculiarities of the function (if there<br />

are any), such as symmetry, periodicity, constancy of sign, monotonicity, etc.<br />

Then f<strong>in</strong>d any po<strong>in</strong>ts of discont<strong>in</strong>uity, bend<strong>in</strong>g po<strong>in</strong>ts, po<strong>in</strong>ts of <strong>in</strong>flection,<br />

asym<strong>pt</strong>otes, etc. These elements help to determ<strong>in</strong>e the general nature of the<br />

graph of the function and to obta<strong>in</strong> a mathematically correct outl<strong>in</strong>e of it.<br />

Example 1. Construct the graph of the function<br />

Solution, a) The function exists everywhere exce<strong>pt</strong> at the po<strong>in</strong>ts x 1.<br />

The function is odd, and therefore the graph is symmetric about the po<strong>in</strong>t<br />

0(0, 0). This simplifies construction of the graph<br />

b) The discont<strong>in</strong>uities are x= 1 and jc 1; and lim J/= oo and<br />

V-M + O<br />

lim t/=oo; hence, the straight l<strong>in</strong>es #=1 are vertical asym<strong>pt</strong>otes of the<br />

X->--10<br />

graph.<br />

c) We seek <strong>in</strong>cl<strong>in</strong>ed asym<strong>pt</strong>otes, and f<strong>in</strong>d<br />

,= lim -- = 0,<br />

X -> + oo x<br />

b l lim y oo,<br />

#->-t-oo<br />

thus, there is no right asym<strong>pt</strong>ote. From the symmetry of the curve it follows<br />

that there is no left-hand asym<strong>pt</strong>ote either.<br />

d) We f<strong>in</strong>d the critical po<strong>in</strong>ts of the first and second k<strong>in</strong>ds, that is,<br />

po<strong>in</strong>ts at which the first (or, respectively, the second) derivative of the given<br />

function vanishes or does not exist.<br />

We have: ,<br />

The derivatives y' and \f are nonexistent only at x=l, that is, only at<br />

po<strong>in</strong>ts where the function y itself does not exist; and so the critical po<strong>in</strong>ts<br />

are only those at which y' and y" vanish.<br />

From (1) and (2) it follows that<br />

y'=Q when x= V$\<br />

r/" = when x = and x= 3.<br />

Thus, y' reta<strong>in</strong>s a<br />

constant_ sign <strong>in</strong> each of the <strong>in</strong>tervals ( 00, J/T),<br />

(-V3, l), (1, 1), (l, V$) and (V~3 t +00), and / <strong>in</strong> each of the<br />

<strong>in</strong>tervals ( 00, 3), ( 3, 1), (1, 0), (0, 1), (1, 3) and (3, +00).<br />

To determ<strong>in</strong>e the signs of y' (or, respectively, y") <strong>in</strong> each of the <strong>in</strong>dicated<br />

<strong>in</strong>tervals, it is sufficient to determ<strong>in</strong>e the sign of y' (or y") at some one po<strong>in</strong>t<br />

of each of these <strong>in</strong>tervals.

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