Research Methodology - Dr. Krishan K. Pandey
Research Methodology - Dr. Krishan K. Pandey Research Methodology - Dr. Krishan K. Pandey
Sampling Design 63 The following three questions are highly relevant in the context of stratified sampling: (a) How to form strata? (b) How should items be selected from each stratum? (c) How many items be selected from each stratum or how to allocate the sample size of each stratum? Regarding the first question, we can say that the strata be formed on the basis of common characteristic(s) of the items to be put in each stratum. This means that various strata be formed in such a way as to ensure elements being most homogeneous within each stratum and most heterogeneous between the different strata. Thus, strata are purposively formed and are usually based on past experience and personal judgement of the researcher. One should always remember that careful consideration of the relationship between the characteristics of the population and the characteristics to be estimated are normally used to define the strata. At times, pilot study may be conducted for determining a more appropriate and efficient stratification plan. We can do so by taking small samples of equal size from each of the proposed strata and then examining the variances within and among the possible stratifications, we can decide an appropriate stratification plan for our inquiry. In respect of the second question, we can say that the usual method, for selection of items for the sample from each stratum, resorted to is that of simple random sampling. Systematic sampling can be used if it is considered more appropriate in certain situations. Regarding the third question, we usually follow the method of proportional allocation under which the sizes of the samples from the different strata are kept proportional to the sizes of the strata. That is, if P i represents the proportion of population included in stratum i, and n represents the total sample size, the number of elements selected from stratum i is n . P i . To illustrate it, let us suppose that we want a sample of size n = 30 to be drawn from a population of size N = 8000 which is divided into three strata of size N 1 = 4000, N 2 = 2400 and N 3 = 1600. Adopting proportional allocation, we shall get the sample sizes as under for the different strata: For strata with N 1 = 4000, we have P 1 = 4000/8000 and hence n 1 = n . P 1 = 30 (4000/8000) = 15 Similarly, for strata with N 2 = 2400, we have n 2 = n . P 2 = 30 (2400/8000) = 9, and for strata with N 3 = 1600, we have n 3 = n . P 3 = 30 (1600/8000) = 6. Thus, using proportional allocation, the sample sizes for different strata are 15, 9 and 6 respectively which is in proportion to the sizes of the strata viz., 4000 : 2400 : 1600. Proportional allocation is considered most efficient and an optimal design when the cost of selecting an item is equal for each stratum, there is no difference in within-stratum variances, and the purpose of sampling happens to be to estimate the population value of some characteristic. But in case the purpose happens to be to compare the differences among the strata, then equal sample selection from each stratum would be more efficient even if the strata differ in sizes. In cases where strata differ not only in size but also in variability and it is considered reasonable to take larger samples from the more variable strata and smaller samples from the less variable strata, we can then account for both (differences in stratum size and differences in stratum variability) by using disproportionate sampling design by requiring:
64 Research Methodology n / N σ = n / N σ = ......... = n / N σ 1 1 1 2 2 2 k k k where σ1, σ2, ... and σ k denote the standard deviations of the k strata, N , N ,…, N denote the 1 2 k sizes of the k strata and n , n ,…, n denote the sample sizes of k strata. This is called ‘optimum 1 2 k allocation’ in the context of disproportionate sampling. The allocation in such a situation results in the following formula for determining the sample sizes different strata: n i n ⋅ Ni σi = N σ + N σ + + N σ 1 1 2 2 ... We may illustrate the use of this by an example. k k for i = 1, 2, … and k. Illustration 1 A population is divided into three strata so that N 1 = 5000, N 2 = 2000 and N 3 = 3000. Respective standard deviations are: σ = 15, σ = 18 and σ = 5. 1 2 3 How should a sample of size n = 84 be allocated to the three strata, if we want optimum allocation using disproportionate sampling design? Solution: Using the disproportionate sampling design for optimum allocation, the sample sizes for different strata will be determined as under: Sample size for strata with N 1 = 5000 n1 = 84b5000gb15g b5000gb15g + b2000gb18g + b3000gbg 5 = 6300000/126000 = 50 Sample size for strata with N 2 = 2000 n 2 Sample size for strata with N 3 = 3000 n 3 = = 84b2000gb18g b5000gb15g + b2000gb18g + b3000gbg 5 = 3024000/126000 = 24 84b3000gbg 5 b5000gb15g + b2000gb18g + b3000gbg 5 = 1260000/126000 = 10 In addition to differences in stratum size and differences in stratum variability, we may have differences in stratum sampling cost, then we can have cost optimal disproportionate sampling design by requiring n1 n2 nk = = ... = N σ C N σ C N σ C 1 1 1 2 2 2 k k k
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- Page 72 and 73: Sampling Design 55 CENSUS AND SAMPL
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64 <strong>Research</strong> <strong>Methodology</strong><br />
n / N σ = n / N σ = ......... = n / N σ<br />
1 1 1 2 2 2<br />
k k k<br />
where σ1, σ2,<br />
... and σ k denote the standard deviations of the k strata, N , N ,…, N denote the<br />
1 2 k<br />
sizes of the k strata and n , n ,…, n denote the sample sizes of k strata. This is called ‘optimum<br />
1 2 k<br />
allocation’ in the context of disproportionate sampling. The allocation in such a situation results in<br />
the following formula for determining the sample sizes different strata:<br />
n<br />
i<br />
n ⋅ Ni<br />
σi<br />
=<br />
N σ + N σ + + N σ<br />
1 1 2 2 ...<br />
We may illustrate the use of this by an example.<br />
k k<br />
for i = 1, 2, … and k.<br />
Illustration 1<br />
A population is divided into three strata so that N 1 = 5000, N 2 = 2000 and N 3 = 3000. Respective<br />
standard deviations are:<br />
σ = 15, σ = 18 and σ = 5.<br />
1 2 3<br />
How should a sample of size n = 84 be allocated to the three strata, if we want optimum allocation<br />
using disproportionate sampling design?<br />
Solution: Using the disproportionate sampling design for optimum allocation, the sample sizes for<br />
different strata will be determined as under:<br />
Sample size for strata with N 1 = 5000<br />
n1 =<br />
84b5000gb15g b5000gb15g + b2000gb18g + b3000gbg 5<br />
= 6300000/126000 = 50<br />
Sample size for strata with N 2 = 2000<br />
n 2<br />
Sample size for strata with N 3 = 3000<br />
n 3<br />
=<br />
=<br />
84b2000gb18g b5000gb15g + b2000gb18g + b3000gbg 5<br />
= 3024000/126000 = 24<br />
84b3000gbg 5<br />
b5000gb15g + b2000gb18g + b3000gbg 5<br />
= 1260000/126000 = 10<br />
In addition to differences in stratum size and differences in stratum variability, we may have<br />
differences in stratum sampling cost, then we can have cost optimal disproportionate sampling design<br />
by requiring<br />
n1<br />
n2<br />
nk<br />
= = ...<br />
=<br />
N σ C N σ C N σ C<br />
1 1 1<br />
2 2 2<br />
k k k