Research Methodology - Dr. Krishan K. Pandey

Chi-square Test 245
Events or Expected frequencies
No. of heads
3
4
5
6
7
8
The value of χ 2 can be worked out as follows:
∴
8
8
8
8
Table 10.8
3
1
2
3 5
1
2
256 56
C F H G I K J F H G I K J × =
4
1
2
4 4
1
2
256 70
C F H G I K J F H G I K J × =
5
1
2
5 3
1
2
256 56
C F H G I K J F H G I K J × =
6
1
2
6 2
1
2
256 28
C F H G I K J F H G I K J × =
8 7
1
2
7 1
1
2
256 8
C F H G I K J F H G I K J × =
8 8
1
2
8 0
1
2
256 1
C F H G I K J F H G I K J × =
No. of heads Observed Expected O – E i i (O – E ) i i 2 /Ei frequency frequency
Oi Ei 0 2 1 1 1/1 = 1.00
1 6 8 –2 4/8 = 0.50
2 30 28 2 4/28 = 0.14
3 52 56 –4 16/56 = 0.29
4 67 70 –3 9/70 = 0.13
5 56 56 0 0/56 = 0.00
6 32 28 4 16/28 = 0.57
7 10 8 2 4/8 = 0.50
8 1 1 0 0/1 = 0.00
χ 2
bOi −Eig
=∑
E
i
2
= 3.13