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Research Methodology - Dr. Krishan K. Pandey

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Testing of Hypotheses I 213<br />

Table 9.7<br />

Sample one Sample two<br />

S.No. X1i X – A 1i 1<br />

2<br />

X1i A1<br />

− b g S.No. X2i X – A 2i 2 X2 A −<br />

(A 1 = 10) (A 2 = 8)<br />

2 b i 2g<br />

1. 12 2 4 1. 8 0 0<br />

2. 15 5 25 2. 10 2 4<br />

3. 11 1 1 3. 14 6 36<br />

4. 16 6 36 4. 10 2 4<br />

5. 14 4 16 5. 13 5 25<br />

6. 14 4 16<br />

7. 16 6 36<br />

2<br />

n = 7; ∑bX − A =<br />

1 1i 1g 28;<br />

∑bX1i − A1g<br />

n = 5; ∑bX − A =<br />

2 2i 2g 15;<br />

∑ X2i − A2<br />

= 134 = 69<br />

∑ X i − A<br />

∴ X1= A1+<br />

n<br />

∑ X i − A<br />

X2 = A2<br />

+<br />

n<br />

σ s<br />

σ s<br />

Hence, t =<br />

b 1<br />

1<br />

1g<br />

28<br />

= 10 + = 14 ounces<br />

7<br />

b 2<br />

2<br />

2g<br />

15<br />

= 8 + = 11 ounces<br />

5<br />

b g<br />

b<br />

2<br />

− b g /<br />

b<br />

g<br />

g<br />

2<br />

2 1i 1<br />

1i 1<br />

=<br />

1<br />

n1<br />

1<br />

∑ − − ∑ −<br />

−<br />

X A X A / n<br />

134 28 7<br />

=<br />

= 3667 . ounces<br />

7 − 1<br />

=<br />

b g b g<br />

2<br />

=<br />

2<br />

2i 2<br />

2<br />

2<br />

2i 2<br />

∑ − − ∑ −<br />

2 bg /<br />

b g<br />

X A X A / n<br />

n − 1<br />

69 − 15 5<br />

= 6 ounces<br />

5 − 1<br />

14 − 11<br />

7 − 1 3. 667 + 5 − 1 6<br />

7 + 5 − 2<br />

b gb g b gbg<br />

2<br />

2<br />

1<br />

2<br />

1<br />

× +<br />

7<br />

1<br />

5<br />

b g<br />

2

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