Research Methodology - Dr. Krishan K. Pandey
Research Methodology - Dr. Krishan K. Pandey Research Methodology - Dr. Krishan K. Pandey
Testing of Hypotheses I 207 S. No. X i Table 9.4 Xi X − d i Xi X − d i 2 1 550 2 4 2 570 22 484 3 490 –58 3364 4 615 67 4489 5 505 –43 1849 6 580 32 1024 7 570 22 484 8 460 –88 7744 9 600 52 2704 10 580 32 1024 11 530 –18 324 12 526 –22 484 d i i 2 n = 10 ∑ Xi = 6576 ∑ X − X = 23978 ∴ X and σ s = ∑ − X = n ∑ i 6576 = = 12 dXiXi 2 n − 1 = 548 23978 = 12 − 1 548 − 500 48 Hence, t = = = 3558 . 46. 68/ 12 13. 49 46. 68 Degree of freedom = n – 1 = 12 – 1 = 11 As H a is one-sided, we shall determine the rejection region applying one-tailed test (in the right tail because H a is of more than type) at 5 per cent level of significance and it comes to as under, using table of t-distribution for 11 degrees of freedom: R : t > 1.796 The observed value of t is 3.558 which is in the rejection region and thus H 0 is rejected at 5 per cent level of significance and we can conclude that the sample data indicate that Raju restaurant’s sales have increased. HYPOTHESIS TESTING FOR DIFFERENCES BETWEEN MEANS In many decision-situations, we may be interested in knowing whether the parameters of two populations are alike or different. For instance, we may be interested in testing whether female workers earn less than male workers for the same job. We shall explain now the technique of
208 Research Methodology hypothesis testing for differences between means. The null hypothesis for testing of difference : μ = μ , where μ1 is population mean of one population between means is generally stated as H 0 1 2 and μ 2 is population mean of the second population, assuming both the populations to be normal populations. Alternative hypothesis may be of not equal to or less than or greater than type as stated earlier and accordingly we shall determine the acceptance or rejection regions for testing the hypotheses. There may be different situations when we are examining the significance of difference between two means, but the following may be taken as the usual situations: 1. Population variances are known or the samples happen to be large samples: In this situation we use z-test for difference in means and work out the test statistic z as under: z = X − X 1 2 2 2 p p2 σ 1 σ + n n 1 In case σ p1 and σ p2 are not known, we use σ s1 and σ s2 respectively in their places calculating 2 2 d i d 2 2i X1i X1 X i X σs = σ 1 s2 n 1 n 1 ∑ − = − ∑ − and − 1 2. Samples happen to be large but presumed to have been drawn from the same population whose variance is known: In this situation we use z test for difference in means and work out the test statistic z as under: z = In case σ p is not known, we use σ s12 . in its place calculating d i d i where D = X − X . 1 1 12 D = X − X . 2 2 12 σ s 12 . = σ X − X 2 p F HG 1 2 2 1 1 + n n 1 2 I KJ 2 (combined standard deviation of the two samples) 2 2 2 2 1e s1 1j 2e s2 2j n σ + D + n σ + D n + n 1 2
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208 <strong>Research</strong> <strong>Methodology</strong><br />
hypothesis testing for differences between means. The null hypothesis for testing of difference<br />
: μ = μ , where μ1 is population mean of one population<br />
between means is generally stated as H 0 1 2<br />
and μ 2 is population mean of the second population, assuming both the populations to be normal<br />
populations. Alternative hypothesis may be of not equal to or less than or greater than type as stated<br />
earlier and accordingly we shall determine the acceptance or rejection regions for testing the<br />
hypotheses. There may be different situations when we are examining the significance of difference<br />
between two means, but the following may be taken as the usual situations:<br />
1. Population variances are known or the samples happen to be large samples:<br />
In this situation we use z-test for difference in means and work out the test statistic z as<br />
under:<br />
z =<br />
X − X<br />
1 2<br />
2 2<br />
p p2<br />
σ 1 σ<br />
+<br />
n n<br />
1<br />
In case σ p1 and σ p2 are not known, we use σ s1 and σ s2 respectively in their places<br />
calculating<br />
2<br />
2<br />
d i d 2 2i<br />
X1i X1<br />
X i X<br />
σs = σ<br />
1 s2<br />
n 1 n 1<br />
∑ −<br />
=<br />
−<br />
∑ −<br />
and<br />
−<br />
1<br />
2. Samples happen to be large but presumed to have been drawn from the same<br />
population whose variance is known:<br />
In this situation we use z test for difference in means and work out the test statistic z as<br />
under:<br />
z =<br />
In case σ p is not known, we use σ s12 .<br />
in its place calculating<br />
d i<br />
d i<br />
where D = X − X .<br />
1 1 12<br />
D = X − X .<br />
2 2 12<br />
σ<br />
s<br />
12<br />
. =<br />
σ<br />
X − X<br />
2<br />
p<br />
F<br />
HG<br />
1 2<br />
2<br />
1 1<br />
+<br />
n n<br />
1 2<br />
I<br />
KJ<br />
2<br />
(combined standard deviation of the two samples)<br />
2 2<br />
2 2<br />
1e<br />
s1 1j<br />
2e<br />
s2<br />
2j<br />
n σ + D + n σ + D<br />
n + n<br />
1 2