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Research Methodology - Dr. Krishan K. Pandey

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176 <strong>Research</strong> <strong>Methodology</strong><br />

σ p = standard deviation of the popultion (to be estimated from past experience or on the basis of<br />

a trial sample). Suppose, we have σ p = 48<br />

. for our purpose.<br />

If the difference between μ and X or the acceptable error is to be kept with in ±3 of the sample<br />

mean with 95% confidence, then we can express the acceptable error, ‘e’ as equal to<br />

b g b g<br />

2 2<br />

p<br />

e = z⋅<br />

n<br />

σ or 3 196 48 .<br />

= .<br />

n<br />

196 . 48 .<br />

Hence, n = = 9834 . ≅ 10.<br />

2 bg 3<br />

In a general way, if we want to estimate μ in a population with standard deviation σ p with an<br />

error no greater than ‘e’ by calculating a confidence interval with confidence corresponding to z, the<br />

necessary sample size, n, equals as under:<br />

z σ<br />

n =<br />

2<br />

e<br />

All this is applicable whe the population happens to be infinite. Bu in case of finite population, the<br />

above stated formula for determining sample size will become<br />

n =<br />

2 2<br />

2 2*<br />

p<br />

2 2 2<br />

σ p<br />

z ⋅ N ⋅σ<br />

b g<br />

N− 1 e + z<br />

* In case of finite population the confidence interval for μ is given by<br />

σ b g<br />

X ± z<br />

p<br />

×<br />

n<br />

N −n<br />

bN − 1g<br />

where bN −ng bN − 1 g is the finite population multiplier and all other terms mean the same thing as stated above.<br />

If the precision is taken as equal to ‘e’ then we have<br />

σ p bN −ng<br />

e = z ×<br />

n N − 1<br />

b g<br />

σ<br />

2 2 p N −n<br />

or e = z ×<br />

n N − 1<br />

b g<br />

or<br />

2<br />

e N − 1<br />

z<br />

=<br />

σ p N z<br />

−<br />

n<br />

σ p n<br />

n<br />

or<br />

2 2 2<br />

e bN − 1g<br />

+ z σ p<br />

2 2<br />

z σ p N<br />

=<br />

n<br />

2<br />

2 2 2 2<br />

2 2<br />

z ⋅ σ p ⋅ N<br />

or n =<br />

e N − 1 + z σ<br />

or<br />

n =<br />

b g<br />

2 2 2<br />

p<br />

2<br />

z ⋅<br />

2<br />

N ⋅σ<br />

p<br />

2 2 2<br />

N − 1 e + z σ p<br />

b g<br />

This is how we obtain the above stated formula for determining ‘n’ in the case of infinite population given the precision<br />

and confidence level.

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