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Research Methodology - Dr. Krishan K. Pandey

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172 <strong>Research</strong> <strong>Methodology</strong><br />

Thus, 90 per cent confidence interval for population mean is<br />

X ± t<br />

σ<br />

= 368 ± 2 353 28 .<br />

. . = 368 . ± 2. 353 14 .<br />

4<br />

s<br />

n<br />

= 36. 8 ± 3. 294 tons per shift.<br />

ESTIMATING POPULATION PROPORTION<br />

b gb g<br />

So far as the point estimate is concerned, the sample proportion (p) of units that have a particular<br />

characteristic is the best estimator of the population proportion bg $p and its sampling distribution, so<br />

long as the sample is sufficiently large, approximates the normal distribution. Thus, if we take a<br />

random sample of 50 items and find that 10 per cent of these are defective i.e., p = .10, we can use<br />

this sample proportion (p = .10) as best estimator of the population proportion bp$ = p = . 10g.<br />

In<br />

case we want to construct confidence interval to estimate a population poportion, we should use the<br />

binomial distribution with the mean of population bg μ = n⋅ p, where n = number of trials, p =<br />

probability of a success in any of the trials and population standard deviation = npq. As the<br />

sample size increases, the binomial distribution approaches normal distribution which we can use for<br />

our purpose of estimating a population proportion. The mean of the sampling distribution of the<br />

proportion of successes ( μp ) is taken as equal to p and the standard deviation for the proportion of<br />

successes, also known as the standard error of proportion, is taken as equal to pq n . But when<br />

population proportion is unknown, then we can estimate the population parameters by substituting the<br />

corresponding sample statistics p and q in the formula for the standard error of proportion to obtain<br />

the estimated standard error of the proportion as shown below:<br />

σ p<br />

=<br />

Using the above estimated standard error of proportion, we can work out the confidence interval<br />

for population proportion thus:<br />

where<br />

p ± z ⋅<br />

p = sample proportion of successes;<br />

q = 1 – p;<br />

n = number of trials (size of the sample);<br />

z = standard variate for given confidence level (as per normal curve area table).<br />

pq<br />

n<br />

pq<br />

n

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