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Research Methodology - Dr. Krishan K. Pandey

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170 <strong>Research</strong> <strong>Methodology</strong><br />

n = 36<br />

X = 40 years<br />

σ s = 45 . years<br />

and the standard variate, z, for 95 per cent confidence is 1.96 (as per the normal curve area table).<br />

Thus, 95 per cent confidence inteval for the mean age of population is:<br />

s X ± z<br />

n<br />

σ<br />

or 40 196 45 .<br />

± .<br />

36<br />

b gb g<br />

or 40 ± 196 . 0. 75<br />

or 40 ± 147 . years<br />

Illustration 2<br />

In a random selection of 64 of the 2400 intersections in a small city, the mean number of scooter<br />

accidents per year was 3.2 and the sample standard deviation was 0.8.<br />

(1) Make an estimate of the standard deviation of the population from the sample standard<br />

deviation.<br />

(2) Work out the standard error of mean for this finite population.<br />

(3) If the desired confidence level is .90, what will be the upper and lower limits of the confidence<br />

interval for the mean number of accidents per intersection per year?<br />

Solution: The given information can be written as under:<br />

N = 2400 (This means that population is finite)<br />

n = 64<br />

X = 32 .<br />

σs = 08 .<br />

and the standard variate (z) for 90 per cent confidence is 1.645 (as per the normal curve area table).<br />

Now we can answer the given questions thus:<br />

(1) The best point estimate of the standard deviation of the population is the standard deviation<br />

of the sample itself.<br />

Hence,<br />

σ$ = σ = 08 .<br />

p s<br />

(2) Standard error of mean for the given finite population is as follows:<br />

σ<br />

X<br />

σ s<br />

= ×<br />

n<br />

N − n<br />

N − 1

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