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Energy output with spulsed <strong>probes</strong><br />
Compared to continuous wave <strong>probes</strong>,<br />
pulsed <strong>probes</strong> emit relatively strong, but<br />
extremely short light pulses sequentially.<br />
The duration of the pulses is always equally<br />
short and equally strong.<br />
The frequency determines the number of<br />
pulses per second and thus the average<br />
power output. The higher the frequency,<br />
the more energy emitted. The following<br />
fi gures indicate the relationship based on<br />
the superpulsed single probe at 90 W. For<br />
illustration, a very small frequency is contrasted<br />
with a large one.<br />
At a frequency of 1 Hz<br />
The pulsed probe has a peak power output<br />
of 90 W. One pulse is emitted per second at<br />
a modulation frequency of 1 Hz.<br />
Leistung<br />
in Watt<br />
100<br />
90<br />
The light frequency amounts to 331 THz,<br />
which corresponds to a wavelength of 904<br />
nm. Each pulse emits energy for a duration<br />
of 100 ns, or 100 billionths of a second.<br />
W<br />
75<br />
50<br />
25<br />
0<br />
331 THz<br />
1<br />
Reimers & Janssen superpulsed <strong>probes</strong><br />
General formulae<br />
total<br />
energy (E)<br />
average<br />
power<br />
output<br />
Pre-set values<br />
100 ns<br />
2<br />
sek.<br />
= average power output (P)<br />
x treatment time (T)<br />
=<br />
3<br />
Zeit<br />
in Sekunden<br />
peak power output<br />
x pulse duration x<br />
frequency<br />
Treatment time = 10 s<br />
Frequency modulation = 1 Hz<br />
Calculation<br />
E = 90 W x 100 ns x 1 Hz x 10 s<br />
4<br />
= 90 W x (100 x 10 -9 )s x 1 Hz x 10s<br />
= 90 µJ (micro Joules)<br />
30
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