The Mitochondrial Free Radical Theory of Aging - Supernova: Pliki
The Mitochondrial Free Radical Theory of Aging - Supernova: Pliki
The Mitochondrial Free Radical Theory of Aging - Supernova: Pliki
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38<br />
<strong>The</strong> <strong>Mitochondrial</strong> <strong>Free</strong> <strong>Radical</strong> <strong>The</strong>ory <strong>of</strong> <strong>Aging</strong><br />
<strong>The</strong> LECs that are discussed throughout the rest <strong>of</strong> this book, and especially in the rest<br />
<strong>of</strong> this chapter, are listed in Table 3.2. Also listed are the molecules which, though not LECs,<br />
are important in MiFRA because they react with LECs and/or are formed by reactions<br />
involving LECs.<br />
3.5. LEC-Related Reactions Relevant to MiFRA<br />
<strong>The</strong> reactions that will concern us in the rest <strong>of</strong> this book are described in Table 3.3;<br />
several <strong>of</strong> the most important destructive ones are also depicted in Figure 3.1. <strong>The</strong> reactions<br />
fall into the following categories:<br />
a. donation <strong>of</strong> an electron by a LEC to a non-LEC — reduction<br />
b. removal <strong>of</strong> an electron by a LEC from a non-LEC — oxidation<br />
c. donation <strong>of</strong> an electron by a LEC to another LEC — usually disproportionation<br />
d. fusion <strong>of</strong> a non-LEC with a LEC forming a LEC — condensation<br />
e. fusion <strong>of</strong> a LEC with another LEC forming a non-LEC — termination<br />
f. fission <strong>of</strong> a LEC forming a LEC and a non-LEC — dissociation<br />
g. reactions not involving LECs but <strong>of</strong> relevance nevertheless<br />
Because some <strong>of</strong> the reactions involve joining or splitting <strong>of</strong> lipids to form other lipids,<br />
the equations that involve more than one lipid use subscripts a, b etc. to distinguish them.<br />
Tables 3.2 and 3.3 may seem rather intimidating, but there is no need to absorb them;<br />
they are supplied here mainly for ease <strong>of</strong> reference through the rest <strong>of</strong> the book. At this<br />
point, the most important thing to appreciate about these reactions is the reason why I<br />
defined “LEC” as I did: as noted in Table 3.1, reactions that happen in biological systems<br />
preserve “LEC parity.” That is, if you start with an odd number <strong>of</strong> LECs you end with an odd<br />
number, and if you start with an even number <strong>of</strong> LECs you end with an even number. This<br />
is not so for free radicals, nor for reactive oxygen species.<br />
It is also worth stressing at this point that not all LECs behave in the same way. For<br />
example, the reaction between two ascorbate radicals and that between two lipid radicals<br />
are completely different: the former involves the incorporation <strong>of</strong> two protons, whereas the<br />
latter uses no protons but instead makes a bond. This is a crucial difference, because the<br />
bond is permanent, whereas the oxidised ascorbate (dehydroascorbate) is still an independent<br />
molecule which can be restored to its reduced form. This property <strong>of</strong> ascorbate, together<br />
with its extreme readiness to undergo disproportionation, is the main reason why it is so<br />
valuable to us.<br />
A third crucial feature which should be observed in this list is that some pairs <strong>of</strong> reactions<br />
cause the change <strong>of</strong> one participant to a different form and then back again. For example,<br />
superoxide turns ferric iron into ferrous, and hydrogen peroxide turns it back to ferric.<br />
Putting those two reactions in sequence:<br />
O2• — + Fe 3+<br />
H2O2 + Fe 2+ • +H +<br />
O2• — + H2O2 +H +<br />
O2 + Fe 2+ •<br />
HO• + H2O + Fe 3+<br />
HO• + H2O + O2<br />
gives us a chemical change which, if thought <strong>of</strong> as a single reaction, doesn’t involve iron at<br />
all.<br />
But that cumulative reaction does not appear in Table 3.3, and the reason it doesn’t<br />
appear is that it doesn’t happen. Iron (or copper, or some other ion that behaves the same<br />
way) needs to be present so that the intermediate state is available. Iron therefore acts as a<br />
catalyst, causing a normally impossible reaction to be achieved by a detour that needs less<br />
activation energy. This is the way that all catalysts work, and why a reaction needs so much