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Simplicial Structures in Topology

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70 II <strong>Simplicial</strong> Complexes<br />

Please notice that if f is cha<strong>in</strong> null-homotopic, then Hn( f )=0foreveryn.<br />

A cha<strong>in</strong> complex (C,∂) is free if all of its groups are free Abelian; it is positive<br />

if Cn = 0foreveryn < 0. A positive cha<strong>in</strong> complex (C,∂ ) is augmented (to Z) if<br />

there exists an epimorphism<br />

ε : C0 → Z<br />

such that ε∂1 = 0. The homomorphism ε is the augmentation (homomorphism).<br />

(II.3.5) Remark. The cha<strong>in</strong> complex C(K) associated with a simplicial complex K<br />

is free and positive. Moreover, the function<br />

is an augmentation.<br />

ε : C0(K) → Z, Σ n i=1 ai{xi} ↦→ Σ n i=1 ai<br />

A cha<strong>in</strong> complex (C,∂) is acyclic if, for every n ∈ Z, ker∂n = im∂n+1, thatisto<br />

say, if the sequence<br />

···<br />

��<br />

Cn+1<br />

∂n+1 ��<br />

Cn<br />

∂n ��<br />

Cn−1<br />

��<br />

···<br />

is exact. A positive cha<strong>in</strong> complex (C,∂ ) with augmentation is acyclic if the<br />

sequence<br />

···<br />

��<br />

Cn<br />

∂n ��<br />

···<br />

∂1 ��<br />

C0<br />

ε ��<br />

��<br />

Z<br />

is exact.<br />

Let (C,∂) and (C ′ ,∂ ′ ) be two positive augmented cha<strong>in</strong> complexes. A morphism<br />

f ∈ C((C,∂),(C ′ ,∂ ′ )) is an extension of a homomorphism ¯f : Z → Z if the next<br />

diagram commutes.<br />

···<br />

···<br />

��<br />

C1<br />

f1<br />

��<br />

��<br />

′<br />

C 1<br />

∂1 ��<br />

f0<br />

C0<br />

��<br />

∂ ′ 1 ��<br />

′<br />

C 0<br />

ε ��<br />

��<br />

ε ′<br />

Z<br />

��<br />

��<br />

��<br />

Z<br />

(II.3.6) Theorem. Let (C,∂) and (C ′ ,∂ ′ ) be positive augmented cha<strong>in</strong> complexes;<br />

assume that (C,∂) is free and (C ′ ,∂ ′ ) is acyclic. Then any homomorphism<br />

¯f : Z → Z admits an extension f : (C,∂) → (C ′ ,∂ ′ ), unique up to cha<strong>in</strong><br />

homotopy.<br />

Proof. S<strong>in</strong>ce the augmentation ε ′ : C ′ 0 → Z is surjective, for every basis element x0<br />

of C0, we choose an element of C ′ 0 which is taken onto ¯f ε(x0) by ε ′ ;<strong>in</strong>thisway,we<br />

obta<strong>in</strong> a homomorphism f0 : C0 → C ′ 0 such that ¯f ε = ε ′ f0. We now take an arbitrary<br />

basis element x1 of C1; because<br />

¯f

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