Simplicial Structures in Topology
Simplicial Structures in Topology
Simplicial Structures in Topology
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26 I Fundamental Concepts<br />
every i = 1,...,n, the metric d(−,X � Ai): X → R≥0 is cont<strong>in</strong>uous. Hence, the<br />
function<br />
f : X → R≥0 , f = max{d(−,X � Ai) | i = 1,...,n}<br />
is cont<strong>in</strong>uous. By Theorem (I.1.26), f (X) is a compact subspace of R and then, by<br />
Theorem (I.1.25), f (X) is closed <strong>in</strong> R. On the other hand, we note that for any x ∈ X<br />
there exists a certa<strong>in</strong> Ai such that x ∈ Ai and, s<strong>in</strong>ce X � Ai is closed, d(x,X � Ai) > 0<br />
(see Corollary (I.1.43)); and so, for every x ∈ X, f (x) > 0. Therefore, ℓ = <strong>in</strong>f{ f (x) |<br />
x ∈ X} > 0. It follows that for every x ∈ X, f (x) ≥ ℓ and then d(x,Ai) ≥ ℓ for some<br />
Ai ∈ A; we conclude that ˚Dℓ(x) ⊂ Ai. �<br />
Exercises<br />
1. Let X be a given set; prove that<br />
is a basis for the discrete topology on X.<br />
B = {{x} |x ∈ X}<br />
2. Let B and B ′ be bases for the topologies A and A ′ on the set X. Provethat<br />
A ′ ⊃ A ⇐⇒ (∀x ∈ X)(∀B ∈ B)x ∈ B,(∃B ′ ∈ B ′ ) x ∈ B ′ ⊂ B,<br />
that is to say, prove that A ′ is f<strong>in</strong>er than A if and only if, for every x ∈ X and every<br />
B ∈ B conta<strong>in</strong><strong>in</strong>g x, there exists B ′ ∈ B ′ conta<strong>in</strong><strong>in</strong>g x and conta<strong>in</strong>ed <strong>in</strong> B.<br />
3. Take the follow<strong>in</strong>g segments of the real l<strong>in</strong>e R<br />
(a,b)={x ∈ R | a < x < b},<br />
[a,b)={x ∈ R | a ≤ x < b},<br />
(a,b]={x ∈ R | a < x ≤ b}.<br />
Now take the follow<strong>in</strong>g sets of subsets of R:<br />
B1 = {(a,b) | a < b},<br />
B2 = {[a,b) | a < b},<br />
B3 = {(a,b] | a < b},<br />
B4 = B1 ∪{B � K | B ∈ B1}, with K = {1/n | n ∈ N}.<br />
Prove that Bi, i = 1,2,3,4, are bases for topologies on R and compare these<br />
topologies.<br />
4. Let X and Y be topological spaces with topologies A and AY , respectively. Let<br />
be the X and Y projection.<br />
Prove that the set<br />
π1 : X ×Y → X<br />
π2 : X ×Y → Y<br />
S = {π −1<br />
1 (U) |U ∈ A}∪{π−1 2 (V ) |V ∈ AY }<br />
is a sub-basis for the product topology on X ×Y.