Simplicial Structures in Topology
Simplicial Structures in Topology
Simplicial Structures in Topology
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24 I Fundamental Concepts<br />
<strong>in</strong>duces the commutative diagram<br />
ˆh<br />
X ��<br />
M(Z,W )<br />
��<br />
��<br />
��<br />
q ��<br />
��<br />
ˆg<br />
��<br />
��<br />
��<br />
Y<br />
Suppose that h is cont<strong>in</strong>uous; then, by Theorem (I.1.37), ˆh is cont<strong>in</strong>uous. S<strong>in</strong>ce<br />
q is a quotient map, ˆg is cont<strong>in</strong>uous. Hence, by Theorem (I.1.39), themapg is<br />
cont<strong>in</strong>uous. �<br />
I.1.5 Lebesgue Number<br />
We beg<strong>in</strong> this section by describ<strong>in</strong>g an important class of topological spaces, the<br />
class of metric spaces. LetX be a given set; a metric on X is a function d def<strong>in</strong>ed<br />
from X × X to the set of the non-negative real numbers R≥0, with the follow<strong>in</strong>g<br />
properties:<br />
(∀x,y ∈ X) d(x,y)=d(y,x)<br />
d(x,y)=0 ⇐⇒ x = y<br />
(∀x,y,z ∈ X) d(x,z) ≤ d(x,y)+d(y,z).<br />
A first example is the Euclidean metric on R n ; it may be generalized as follows:<br />
Let V be a vector space with a norm || || and let X be a subset of V; the function<br />
d : X × X → R≥0 def<strong>in</strong>ed by<br />
(∀x,y ∈ X) d(x,y)=||x − y||<br />
is a metric on X. In Sect. II.2 we shall give an important example of metric.<br />
We already have seen that the Euclidean metric def<strong>in</strong>es a topology on R n .<br />
Ametricd on a set X def<strong>in</strong>es a topology on X <strong>in</strong> a similar way to the one described<br />
for R n . In fact, for every x ∈ X and for every real number ε > 0, let<br />
˚Dε(x) ={y ∈ X | d(x,y) < ε} be the open disk of centre x and radius ε; theset<br />
B = { ˚Dε(x) | x ∈ X, ε > 0} is a basis of open sets for X (this proof is similar to the<br />
one for R n ); let U be the set of open sets def<strong>in</strong>ed by B. ThesetX with the topology<br />
U is a topological space called metric space.<br />
We now look <strong>in</strong>to the follow<strong>in</strong>g question: given a metric space X and a cover<strong>in</strong>g<br />
A, is there a positive real number r so that the cover<strong>in</strong>g B = { ˚Dr(x)|x ∈ X} of X is a<br />
ref<strong>in</strong>ement of A ? Obviously, if r has this property, so does any positive real number<br />
s < r. Hence, the set L of positive real numbers r such that B is a ref<strong>in</strong>ement of A<br />
is either the empty set or an open <strong>in</strong>terval (0,t) (<strong>in</strong>clud<strong>in</strong>g the case t = ∞). If L �= /0,<br />
the real number ℓ = supL is the Lebesgue number of the cover<strong>in</strong>g A.