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Simplicial Structures in Topology

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212 VI Homotopy Groups<br />

Proof. S<strong>in</strong>ce K is connected, we may neglect writ<strong>in</strong>g the base po<strong>in</strong>t and simply refer<br />

to π(|K|). We def<strong>in</strong>e the function<br />

ϕ : π(|K|) → H1(|K|;Z)<br />

as follows: let [z] be a generator of H1(S 1 ;Z); then,<br />

(∀[ f ] ∈ π(|K|))ϕ([ f ]) := H1( f ;Z)([z]).<br />

This def<strong>in</strong>ition is <strong>in</strong>dependent from the representative chosen for the homotopy class<br />

[ f ]. We now wish to make sure that ϕ is a group homomorphism. In fact, for every<br />

[ f ],[g] ∈ π(|K|),<br />

because<br />

ϕ([ f ] ν<br />

× [g]) = ϕ([σ( f ∨ g)ν]) = ϕ([ f ]) + ϕ([g])<br />

H1(ν;Z) : H1(S 1 ,Z) → H1(S 1 ∨ S 1 ;Z) ∼ = H1(S 1 ;Z) ⊕ H1(S 1 ;Z),<br />

[z] ↦→ ([z],[z]);<br />

H1( f ∨ g;Z) : H1(S 1 ;Z) ⊕ H1(S 1 ;Z) → H1(|K|;Z) ⊕ H1(|K|;Z),<br />

H1( f ∨ g;Z)([z],[z]) = (H1( f ;Z)([z]),H1(g;Z)([z]));<br />

H1(σ;Z) : H1(|K|∨|K|;Z) → H1(|K|;Z),<br />

(H1( f ;Z)([z]),H1(g;Z)([z])) ↦→ H1( f ;Z)([z]) + H1(g;Z)([z]).<br />

The homomorphism ϕ is surjective: <strong>in</strong> fact, let c = ∑i miσ i 1 be a 1-cycle of the<br />

one-dimensional C1(|K|;Z). Wetakeavertex∗of |K| as the base po<strong>in</strong>t of π(|K|);<br />

for each 1-simplex σ i 1 of c, letσi 1 (0) be its first vertex and σ i 1 (1) its second one;<br />

s<strong>in</strong>ce K is connected, for each 1-simplex σ i 1 of c, there is a path of 1-simplexes λ i 0<br />

(respectively, λ i 1 ) that jo<strong>in</strong>s ∗ to σ i 1 (0) (respectively, σ i 1 (1)). The homotopy class<br />

of the loop λ i 0 .σ i 1 .(λ i 1 )−1 , obta<strong>in</strong>ed by composition, is an element [ fi] ∈ π(|K|,∗);<br />

hence, with a suitable triangulation of S 1 ,wemaysaythat<br />

ϕ( ν<br />

×i ( fi) mi )=∑ i<br />

mi{λ i 0 .σ i 1 .(λ i 1 )−1 }.<br />

However, s<strong>in</strong>ce |K| is connected, each λ i 0 .σ i 1 .(λ i 1 )−1 is homologous to σ i 1 and so, ϕ<br />

is surjective.<br />

The surjection ϕ : π(|K|) → H1(|K|;Z) is easily extended to a surjection<br />

ϕ : π(|K|)/[π(|K|),π(|K|)] → H1(|K|;Z).<br />

We now prove that ϕ is <strong>in</strong>jective. Let us suppose [ f ] ∈ π(|K|) to be such that<br />

ϕ([ f ]) = 0 ∈ H1(|K|;Z); then, ϕ([ f ]) is a boundary<br />

ϕ([ f ]) = ∂2<br />

�<br />

∑ i<br />

miσ 2<br />

i<br />

�<br />

.

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