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Simplicial Structures in Topology

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210 VI Homotopy Groups<br />

Exercises<br />

1. Let X be the space def<strong>in</strong>ed by the union of the unit circle S 1 and the closed<br />

segment [(4,0),(5,0)]; take the vertices a0 =(1,0) and a1 =(4,0). Prove that the<br />

fundamental groups of X based at a0 and a1 are not isomorphic.<br />

2. Let f : (Y,y0) → (X,x0) be a homotopy equivalence. Prove that π(Y,y0) ∼ =<br />

π(X,x0).<br />

3. Let (X,x0) and (Y,y0) be two topological-based spaces. Prove that π(X ×Y,x0 ×<br />

y0) ∼ = π(X,x0) × π(Y,y0).<br />

VI.2 Fundamental Group and Homology<br />

Let ∗ be a generic base po<strong>in</strong>t of either nT 2 or nRP 2 ; by Theorem (VI.1.15),<br />

π(nT 2 ,∗) ∼ = Gp(a1,b1,a2,b2,...,an,bn;a 1 1b 1 1a −1<br />

1 b−1<br />

1 ...a 1 nb 1 na −1<br />

n b −1<br />

n )<br />

π(nRP 2 ,∗) ∼ = Gp(a1,a2,...,an;a 1 1a 1 1 ...a 1 na 1 n).<br />

For n ≥ 2, these groups are not Abelian; to better understand whether they are<br />

isomorphic, we resort to a little algebraic trick: we abelianize them. An element of<br />

the form ghg −1 h −1 of a given group G is called a commutator of G; the subset of G<br />

[G,G]={x ∈ G|x = ghg −1 h −1 , g,h ∈ G}<br />

is a normal subgroup of G known as the commutator subgroup of G and is the<br />

smallest subgroup H of G for which G/H is Abelian. The Abelian group G/[G,G]<br />

is called the abelianized group of G.<br />

(VI.2.1) Lemma. A group homomorphism φ : G → H <strong>in</strong>duces a homomorphism<br />

¯φ : G/[G,G] → H/[H,H]<br />

such that the follow<strong>in</strong>g diagram commutes:<br />

G<br />

��<br />

G/[G,G]<br />

φ<br />

¯φ<br />

��<br />

H<br />

��<br />

��<br />

H/[H,H]<br />

Moreover, if φ is an isomorphism then also ¯φ is an isomorphism.

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