15.01.2013 Views

Simplicial Structures in Topology

Simplicial Structures in Topology

Simplicial Structures in Topology

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

190 V Triangulable Manifolds<br />

The def<strong>in</strong>ition of orientability as given here is obviously <strong>in</strong>complete and not very<br />

useful: <strong>in</strong> fact, a good def<strong>in</strong>ition must be <strong>in</strong>dependent from the triangulation and<br />

based on an <strong>in</strong>variant by homeomorphisms. The next result is meant to correct this<br />

flaw.<br />

(V.3.2) Theorem. Let |K| be a triangulable n-manifold; 6 then<br />

Hn(|K|;Z) ∼ = Z ⇐⇒ |K| is orientable.<br />

Proof. Let us suppose that |K| is orientable and let z = ∑σ be the formal sum of all<br />

n-simplexes of K. The def<strong>in</strong>ition of orientability implies that z and all its <strong>in</strong>tegral<br />

multiples are n-cycles. On the other hand, if z ′ ∈ Zn(K) has a term which is a<br />

multiple rτ of an n-simplex τ, then the terms of z ′ are of the form rτ ′ ,whereτ ′ runs<br />

over the set of all n-simplexes of K <strong>in</strong>tersect<strong>in</strong>g τ <strong>in</strong> (n − 1)-simplexes (otherwise,<br />

z ′ would not be a cycle); but then, by part 3 of Theorem (V.1.5), z ′ would equal the<br />

formal sum r ∑σ = rz,whereσ runs over the set of all n-simplexes of K. Therefore,<br />

Hn(|K|;Z) ∼ = Z.<br />

With a similar argument we may prove that, conversely, given any orientation of<br />

the n-simplexes of K,then-cycles of Cn(K) are of the type rz where z = ∑±σ and σ<br />

runs over the set of all n-simplexes. S<strong>in</strong>ce ∂n(z)=0, we conclude that it is possible<br />

to give an orientation to the n-simplexes, accord<strong>in</strong>g to the Def<strong>in</strong>ition (V.3.1). �<br />

Because of this last result, the def<strong>in</strong>ition of orientability of a triangulable<br />

n-manifold does not depend on the triangulation; furthermore, two triangulable<br />

connected n-manifolds of the same homotopy type are either both orientable or both<br />

nonorientable.<br />

Let V be a triangulable n-manifold and let us suppose that V ∼ = |K|, whereK =<br />

(X,Φ). We consider the barycentric subdivision K (1) =(Φ,Φ (1) ) and associate<br />

with every simplex σ ∈ Φ (that is to say, a vertex of K (1) ) the subset Bσ of Φ (1)<br />

def<strong>in</strong>ed by<br />

eσ = {{σ,σ 1 ,...,σ r }|σ ⊂ σ 1 ⊂ ...⊂ σ r } .<br />

Note that, if dimσ = p, the dimension of the simplexes of eσ is ≤ n − p; <strong>in</strong> particular,<br />

if dimσ = n, eσ co<strong>in</strong>cides with the vertex σ (namely, the barycenter b(σ) )<br />

of K (1) .<br />

We now consider the closure and the boundary of eσ , that is to say, the simplicial<br />

subcomplexes eσ and • eσ of K (1) (see Sect. III.5). The reader is asked to note that • eσ<br />

is the set of all simplexes of eσ not hav<strong>in</strong>g b(σ) as a vertex; hence,<br />

eσ = • eσ ∗ b(σ)<br />

and, therefore, |eσ | is contractible.<br />

The reader is also asked to review Def<strong>in</strong>itions (III.5.3) and (III.5.5) before turn<strong>in</strong>g<br />

to the next result.<br />

6 We remember that our def<strong>in</strong>ition of triangulable manifold requires K to be connected by<br />

1-simplexes.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!