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Simplicial Structures in Topology

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V.1 Topological Manifolds 175<br />

|Ki| = | •<br />

τ i n| � Int|σ n−1|<br />

(remember that •<br />

τi n is the boundary of τi n – see def<strong>in</strong>ition <strong>in</strong> Sect. II.2).<br />

We note that for each p ∈ Int|σ n−1|, the space S(p) is written as the union<br />

S(p) = �r i=1 |Ki|; besides, |Ki|∩|Kj| = | •<br />

σn−1| for each pair of dist<strong>in</strong>ct exponents<br />

(i, j) with i, j ∈{1,2,...,n}. By apply<strong>in</strong>g the Mayer–Vietoris sequence to the pair<br />

(|K1|,|K2|), we obta<strong>in</strong><br />

Hn−1(|K1|∪|K2|;Z) ∼ = Hn−2(| •<br />

σn−1|;Z) ∼ = Z<br />

(note that | •<br />

σn−1| ∼ = Sn−2 ); we next apply the Mayer–Vietoris sequence to the pair<br />

(|K1|∪|K2|,|K3|) and so on, to get the free group with r − 1 generators<br />

� �<br />

r�<br />

Hn−1<br />

|Ki|;Z<br />

i=1<br />

however,<br />

� �<br />

r�<br />

Hn−1 |Ki|;Z ∼= Hn−1(S(p);Z)<br />

i=1<br />

∼ = Z<br />

and so, r − 1 = 1, that is to say, r = 2.<br />

We now assume that |K| is connected. Then by Lemma (II.4.4), K is connected,<br />

<strong>in</strong> the mean<strong>in</strong>g of the def<strong>in</strong>ition given <strong>in</strong> Sect. II.4 (from the topological po<strong>in</strong>t of<br />

view, |K| is connected if and only if it is path-connected).<br />

Let σn ∈ Φ be any n-simplex. We view the simplicial complex K as the union<br />

of two subcomplexes: (a) the simplicial complex L def<strong>in</strong>ed by all n-simplexes of K<br />

(and their subsimplexes) that may be l<strong>in</strong>ked to σn by a sequence of n-simplexes as<br />

mentioned <strong>in</strong> 3; (b) the simplicial complex M of all n-simplexes of K for which this<br />

condition does not hold. Note that K = L ∪ M. If M = /0, the assertion is proved;<br />

this occurs when dim|K| = 1 because K is connected; <strong>in</strong>cidentally note that s<strong>in</strong>ce<br />

K is connected L ∩ M �= /0. We now consider M nonempty and dim|K|≥2. Then,<br />

dim(L ∩ M) ≤ n − 2; <strong>in</strong> fact, if σn−1 were an (n − 1)-simplex of both L and M,<br />

σn−1 would be a face of both an n-simplex of L and an n-simplex of M, whichis<br />

impossible because of the def<strong>in</strong>itions. For any vertex x of L ∩ M,<br />

dim(S(x) ∩ L)=dim(S(x) ∩ M)=n − 1<br />

and dim(S(x) ∩ L ∩ M) ≤ n − 3. However, because of 2., every(n − 2)-simplex<br />

of S(x) is a face shared by two (n − 1)-simplexes; thus if (S(x) ∩ L)n−1 and<br />

(S(x) ∩ M)n−1 are the sets of all (n − 1)-simplexes of S(x) ∩ L and S(x) ∩ M,<br />

respectively, the cha<strong>in</strong>s<br />

cL = ∑<br />

τ∈(S(x)∩L) n−1<br />

τ ,<br />

cM = ∑ τ<br />

τ∈(S(x)∩M)n−1<br />

;

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