Simulink Tutorial on Digital Modulation Methods - Cengage Learning
Simulink Tutorial on Digital Modulation Methods - Cengage Learning Simulink Tutorial on Digital Modulation Methods - Cengage Learning
598 CHAPTER 13. SIMULINK TUTORIAL ON DIGITAL MODULATION Figure 13.34: Receiver trajectory for BPSK with NRZ rectangular pulses and matched filter SOLUTION Figure 13.35: Receiver scatter plot for BPSK with NRZ rectangular pulses and matched filter 1. Yes. The maximum vertical eye opening is obtained. Sampling of the trajectory at the optimum sampling time yields the BPSK constellation points. 2. Yes. Now, we examine the respective diagrams at the receiver. TUTORIAL PROBLEM Problem 13.9 [BPSK with NRZ Rectangular Pulses and Matched Filter: Receiver Trajectory, Scatter Plot, and Eye Pattern] 1. Explain the form of the eye pattern. 2. Are vertical and horizontal eye openings maximum? 3. What is the optimum sampling time? 4. Why do we observe more than two signal-space points in the scatter plot at the receiver? SOLUTION 1. The receive filter is implemented as an integrate and dump filter. The waves result from the integration of x(t). Furthermore, the noise is contained in the received signal. 2. Due to additive noise we do not observe the maximum horizontal and vertical eye opening. © 2013 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
13.5. BINARY PHASE-SHIFT KEYING (BPSK) 599 3. t/T = 0, 1, 2,... 4. Because of additive noise. We now consider noiseless transmission. To change the variance of the AWGN, double-click on the blue box Noise variance in the
- Page 1 and 2: Chapter 13 Simulink</strong
- Page 3 and 4: 13.2. SHORT INTRODUCTION TO SIMULIN
- Page 5 and 6: 13.2. SHORT INTRODUCTION TO SIMULIN
- Page 7 and 8: 13.2. SHORT INTRODUCTION TO SIMULIN
- Page 9 and 10: 13.4. PULSE SHAPING 581 Figure 13.1
- Page 11 and 12: 13.4. PULSE SHAPING 583 13.4.1 Theo
- Page 13 and 14: 13.4. PULSE SHAPING 585 Summation o
- Page 15 and 16: 13.4. PULSE SHAPING 587 For α = 0.
- Page 17 and 18: 13.4. PULSE SHAPING 589 Figure 13.1
- Page 19 and 20: 13.4. PULSE SHAPING 591 Figure 13.1
- Page 21 and 22: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 23 and 24: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 25: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 29 and 30: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 31 and 32: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 33 and 34: 13.5. BINARY PHASE-SHIFT KEYING (BP
- Page 35 and 36: 13.6. QUADRATURE PHASE-SHIFT KEYING
- Page 37 and 38: 13.6. QUADRATURE PHASE-SHIFT KEYING
- Page 39 and 40: 13.6. QUADRATURE PHASE-SHIFT KEYING
- Page 41 and 42: 13.6. QUADRATURE PHASE-SHIFT KEYING
- Page 43 and 44: 13.7. OFFSET-QPSK 615 Figure 13.83:
- Page 45 and 46: 13.7. OFFSET-QPSK 617 3. How do the
- Page 47 and 48: 13.7. OFFSET-QPSK 619 Figure 13.98:
- Page 49 and 50: 13.8. MINIMUM SHIFT KEYING (MSK) 62
- Page 51 and 52: 13.8. MINIMUM SHIFT KEYING (MSK) 62
- Page 53 and 54: 13.9. 16-ARY QUADRATURE AMPLITUDE-S
- Page 55 and 56: 13.9. 16-ARY QUADRATURE AMPLITUDE-S
- Page 57 and 58: 13.9. 16-ARY QUADRATURE AMPLITUDE-S
- Page 59 and 60: 13.9. 16-ARY QUADRATURE AMPLITUDE-S
- Page 61: PROBLEMS 633 filter are limited in
598 CHAPTER 13. SIMULINK TUTORIAL ON DIGITAL MODULATION<br />
Figure 13.34: Receiver trajectory for<br />
BPSK with NRZ rectangular pulses and<br />
matched filter<br />
SOLUTION<br />
Figure 13.35: Receiver scatter plot for<br />
BPSK with NRZ rectangular pulses and<br />
matched filter<br />
1. Yes. The maximum vertical eye opening is obtained. Sampling of the trajectory<br />
at the optimum sampling time yields the BPSK c<strong>on</strong>stellati<strong>on</strong> points.<br />
2. Yes.<br />
Now, we examine the respective diagrams at the receiver.<br />
TUTORIAL PROBLEM<br />
Problem 13.9 [BPSK with NRZ Rectangular Pulses and Matched Filter: Receiver<br />
Trajectory, Scatter Plot, and Eye Pattern]<br />
1. Explain the form of the eye pattern.<br />
2. Are vertical and horiz<strong>on</strong>tal eye openings maximum?<br />
3. What is the optimum sampling time?<br />
4. Why do we observe more than two signal-space points in the scatter plot at the<br />
receiver?<br />
SOLUTION<br />
1. The receive filter is implemented as an integrate and dump filter. The waves<br />
result from the integrati<strong>on</strong> of x(t). Furthermore, the noise is c<strong>on</strong>tained in the<br />
received signal.<br />
2. Due to additive noise we do not observe the maximum horiz<strong>on</strong>tal and vertical<br />
eye opening.<br />
© 2013 <strong>Cengage</strong> <strong>Learning</strong>. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.