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CCNA Cisco Certified Network Associate Study Guide - FTP Server

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3. 256–192=64. 64+64=128.<br />

Subnetting 147<br />

4. First find the broadcast addresses in step 5, then come back and perform<br />

step 4 by filling in the host addresses.<br />

5. Find the broadcast address of each subnet, which is always the number<br />

right before the next subnet.<br />

The following table shows the two subnets available, the valid host range,<br />

and the broadcast address of each.<br />

Subnet 64.0 128.0<br />

First Host 64.1 128.1<br />

Last Host 127.254 191.254<br />

Broadcast 127.255 191.255<br />

Notice we just added the fourth octet’s lowest and highest values and<br />

came up with the answers. Again, it is the same answer as for a Class C subnet,<br />

but we just added the fourth octet.<br />

Practice Example 2: 255.255.240.0<br />

172.16.0.0=<strong>Network</strong> address<br />

255.255.240.0=Subnet address<br />

1. 2 4 –2=14.<br />

2. 2 12 –2=4094.<br />

3. 256–240=16, 32, 48, etc., up to 224. Notice these are the same numbers<br />

as a Class C 240 mask.<br />

4. First find the broadcast addresses in step 5, then come back and perform<br />

step 4 by filling in the host addresses.<br />

5. Find the broadcast address of each subnet, which is always the number<br />

right before the next subnet.

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